A linear function has an x-intercept of 12 and a slope of 3/8. How does this function compare to the linear function that is rep
resented by the table? X= -2/3, -1/6, 1/3, 5/8. Y=-3/4, -9/16, -3/8, -3/16. It has the same slope and the same y-intercept. It has the same slope and a different y-intercept. It has the same y-intercept and a different slope. It has a different slope and a different y-intercept.
We rewrite the statement correctly: "A linear function has an y-intercept of 12 and a slope of 3/8" Therefore, the linear function is: y = (3/8) x + 12 We look for the linear function of the table: y-yo = m (x-xo) Where, m = (y2-y1) / (x2-x1) m = ((- 3/8) - (- 3/4)) / ((1/3) - (- 2/3)) m = ((- 3/8) - (- 6/8)) / (3/3) m = ((- 3 + 6) / 8) / (1) m = 3/8 (xo, yo) = (- 2/3, -3/4) Substituting: y + 3/4 = (3/8) (x + 2/3) y = (3/8) x + 2/8 - 3/4 y = (3/8) x + 1/4 - 3/4 y = (3/8) x + -2/4 y = (3/8) x + -1/2 The lines are: y = (3/8) x + 12 y = (3/8) x + -1/2 Answer: It has the same slope and a different y-intercept
