All categories

3 years ago

The equation of the line that goes through the point (−10,8) and (−3,-4) can be written in the form y=mx+b

Mathematics

1 answer:

Y_Kistochka [10]3 years ago

8 0

Answer:

m is -12/7 and b is -64/7

Step-by-step explanation:

Use rise over run (change in y / change in x) to find the slope, m:

(-4 - 8) / (-3 + 10)

= -12/7

So, m is -12/7.

Plug in this value and a point into y = mx + b, then solve for b:

y = mx + b

-4 = -12/7(-3) + b

-4 = 36/7 + b

-64/7 = b

So, m is -12/7 and b is -64/7

You might be interested in

Write the equation for the inverse of the function y=Cos^-1(x-pi)

ser-zykov [4K]

we are given

$y=cos^{-1}(x-\pi)$

Since, we have to find inverse function

step-1:

Set y=f(x)

It is already there

step-2:

Switch x and y

$x=cos^{-1}(y-\pi)$

step-3: Solve for y

We can take cos on both sides

$cos(x)=cos(cos^{-1}(y-\pi))$

we can simplify it

$cos(x)=y-\pi$

now, we can solve for y

$cos(x)+\pi=y-\pi+\pi$

$cos(x)+\pi=y$

$y=\pi +cos(x)$ ..............Answer

3 0

3 years ago

Read 2 more answers

Which of PQ and QR contains P

mestny [16]

PQ contains P... im pretty sure

8 0

3 years ago

Which shows the following expression after the negative exponents have been eliminated?

Mazyrski [523]

Answer:

$a^2b^2$

Step-by-step explanation:

Given the algebraic expression:

$\dfrac{a^3b^{-2}}{ab^{-4}} , a\neq 0, b\neq 0$

We are required to eliminate the negative exponents and find the resulting expression.

Using the Negative Exponent Law of Indices: $x^{-y}=\dfrac{1}{x^y}$

Using the Division Law of Indices: $\dfrac{t^x}{t^y}=t^{x-y}$

Therefore:

$\dfrac{a^3b^{-2}}{ab^{-4}} = a^{3-1}\cdot b^{-2-(-4)}\\$Simplifying\\a^{3-1}\cdot b^{-2-(-4)}=a^2b^{-2+4}\\=a^2b^2\\Therefore:\\\dfrac{a^3b^{-2}}{ab^{-4}}=a^2b^2$

7 0

3 years ago

Read 2 more answers

-3.5 + 7.75 + 6.9 (4.3)

Novay_Z [31]

Answer:

33.92

Step-by-step explanation:

7 0

2 years ago

How does place value help me subtract decimals?

vesna_86 [32]

You know where to line up each digit in the number in the subtraction problem

8 0

3 years ago