So as seen in the previous problem and using the associative propery of multiplication which is a(bc)=(ab)c we can conclude that the order doesn't matter so then we find the part with the positives and negatives so we will see what happens when we multipliy positives and negatives so we remember these rules (+)=positive (-)=negative (+) times (+)=(+) (-) times (-)=(+) (+) times (-)=(-) (-) times (+)=(-)
basically group in pairs and write the signs down to conclude proper signs ex. -2 times 2 times 4 times -3 would be (-2 times +2) times (+4 times -3) or (- times +) times (+ times -)=(-) times (-) =+ basically just do this over and over again untill you get 1 sign
basically the rule is if you multiply 2 pairs of signs, if the signs are the same, then the result is positive if the signs are different, then the result is negative
(+) times (+)=(+) (-) times (-)=(+) (+) times (-)=(-) (-) times (+)=(-)
