N/8 = 25/40
40n = 25 * 8
40n = 200
n = 200/40
n = 5
n/20 = 85/100
100n = 85 * 20
100n = 1700
n = 1700/100
n = 17
2/3 = 16/n
2n = 16 * 3
2n = 48
n = 48/2
n = 24
5/6 = 25/n
5n = 25 * 6
5n = 150
n = 150/5
n = 30
Given function:

The minimum value of the function can be found by setting the first derivative of the function to zero.


Solving for x:


Substituting the value of x into the original function:

Hence, the minimum value in the given range is (-1, -0.368)
Answer:

Step-by-step explanation:
After every Half life , Half of the mass is left.
After 1st Half life = 100 g / 2 = 50 g
After 2nd Half life = 50 / 2 = 25 g
After 3rd Half life = 25 / 2 = 12.5 g
After 4th Half life = 12.5 / 2 = 6.25 g
![\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Crule%5B225%5D%7B225%7D%7B2%7D)
Hope this helped!
<h3>
~AH1807</h3>
Answer:
replace m with 2 and do 7(2)+9