Answer:
The probability of drawing the compliment of a king or a queen from a standard deck of playing cards = 0.846
Step-by-step explanation:
<u><em>Step(i):-</em></u>
Let 'S' be the sample space associated with the drawing of a card
n (S) = 52C₁ = 52
Let E₁ be the event of the card drawn being a king

Let E₂ be the event of the card drawn being a queen

But E₁ and E₂ are mutually exclusive events
since E₁ U E₂ is the event of drawing a king or a queen
<u><em>step(ii):-</em></u>
The probability of drawing of a king or a queen from a standard deck of playing cards
P( E₁ U E₂ ) = P(E₁) +P(E₂)

P( E₁ U E₂ ) = 
<u><em>step(iii):-</em></u>
The probability of drawing the compliment of a king or a queen from a standard deck of playing cards



<u><em>Conclusion</em></u>:-
The probability of drawing the compliment of a king or a queen from a standard deck of playing cards = 0.846
M = (y2-y1)/(x2-x1)
= (4-14)/3-1
= -10/2
= -5
A single drink would cost be $1.55. This is because:
13 + 4x - 6 = 13.20.
(13.20 - 13 + 6) = 6.20.
6.20 / 4 = 1.55
Hope this helped.
Answer:
D) L+S=9 ; 6L+3S=9
Step-by-step explanation:
Given this information, we know that the total number of large and small Ubers must be 9, so we can eliminate choices A and C as the first part of the system of equations is L+S=9
Also, since the large Ubers can fit only 6 people per vehicle and the small Ubers can only fit 3 people per vehicle, then we can eliminate choice B as the second part of the system of equations is 6L+3S=39
Therefore, the only correct choice is D