Answer: A, C, and D
Step-by-step explanation:
A terminating decimal is a decimal that has an end. In other words,
is one, but
is not.
✓ A. 0.032
✗ B. 0.999...
✓ C. 0.525
✓ D. 0.75
Answer:
Probability that a car need to be repaired once = 20% = 0.20
Probability that a car need to be repaired twice = 8% = 0.08
Probability that a car need to be repaired three or more = 2% = 0.02
a) If you own two cars what is the probability that neither will need repair?
Probability that a car need to be repaired once , twice and thrice or more= 0.20+0.08+0.02=0.3
Probability that car need no repair = 1-0.3=0.7
Neither car will need repair=
b) both will need repair?
Probability both will need repair = 
c)at least one car will need repair
Neither car will need repair=
Probability that at least one car will need repair= 1-0.49 = 0.51
Answer:
136+ m ≥ 189 is the required inequality : m: The earning in 4th week
Arthur needs to earn AT LEAST $53 in the fourth week to buy the coat which costs at least $189.
Step-by-step explanation:
The amount earned by Arthur in first 3 weeks = $136
The amount needed to buy a coat = AT LEAST $189
Let us assume the amount Arthur needs to earn more to buy coat = $m
⇒ $ 136 + Amount Earned in 4th week ≥ $189
⇒ 136+ m ≥ 189
The above equation is the NEEDED inequality of the given situation.
Now, solving for the value of m, we get:
136+ m ≥ 189
⇒ m ≥ 189 - 136 = 53
or, m ≥ $53
Hence, Arthur needs to earn AT LEAST $53 in the fourth week to buy the coat which costs at least 189.
81 times 11 is 891
hope this helps u figure out your problem.