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Anastasy [175]
3 years ago
5

a bowl contains 80 M&M candies If 15 are orange what fraction of the candies is NOT orange. Answer reduced to lowest terms

Mathematics
2 answers:
BlackZzzverrR [31]3 years ago
6 0
65/80 can be reduced to 13/16.
kotegsom [21]3 years ago
5 0
So, it says that there are 80 M&M candies in a bowl. 15 are orange, so that means the others aren't orange. So, then you would do (the total number of  M&M candies in the bowl)-(the number of orange M&M candies)=The number of M&M candies that are not orange. So, 80-15=65.
So, they are 65/80 in the bowl that aren't orange. But we aren't done yet. We need to find the lowest term for 65/80. First, we'll need to find what can go into 65 and 80 evenly without leaving a remainder. Yes, you guessed it, five can go into 65 and 80 without leaving a remainder. So, 65 divided by 5=13 and 80 divided by 5=16. So, your final answer is 13/16. 
13/16 is the final answer. This is the lowest possible term for the number pf candies that aren't orange.
65/80=13/16
13/16 are the number of M&M candies that aren't orange.
Hope I helped.
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