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Anastasy [175]
2 years ago
5

a bowl contains 80 M&M candies If 15 are orange what fraction of the candies is NOT orange. Answer reduced to lowest terms

Mathematics
2 answers:
BlackZzzverrR [31]2 years ago
6 0
65/80 can be reduced to 13/16.
kotegsom [21]2 years ago
5 0
So, it says that there are 80 M&M candies in a bowl. 15 are orange, so that means the others aren't orange. So, then you would do (the total number of  M&M candies in the bowl)-(the number of orange M&M candies)=The number of M&M candies that are not orange. So, 80-15=65.
So, they are 65/80 in the bowl that aren't orange. But we aren't done yet. We need to find the lowest term for 65/80. First, we'll need to find what can go into 65 and 80 evenly without leaving a remainder. Yes, you guessed it, five can go into 65 and 80 without leaving a remainder. So, 65 divided by 5=13 and 80 divided by 5=16. So, your final answer is 13/16. 
13/16 is the final answer. This is the lowest possible term for the number pf candies that aren't orange.
65/80=13/16
13/16 are the number of M&M candies that aren't orange.
Hope I helped.
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<em></em>Area = 72in^2<em></em>

<em></em>

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<em>Your question is incomplete without an attachment (See attachment)</em>

Required

Determine the area of the shaded part

From the attachment;

<em>Assume that the shaded portion is closed to the right;</em>

<em>Calculate  the Area:</em>

<em></em>Area_1 = Length * Width<em></em>

<em></em>Area_2 = 8in * (6in + 6in)<em></em>

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<em></em>

<em>Next;</em>

<em>Calculate the Area of the imaginary triangle (on the right)</em>

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<em></em>

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<em></em>Area = 96in^2 - 24in^2<em></em>

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<em></em>

<em>Hence,</em>

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