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Anastasy [175]
2 years ago
5

a bowl contains 80 M&M candies If 15 are orange what fraction of the candies is NOT orange. Answer reduced to lowest terms

Mathematics
2 answers:
BlackZzzverrR [31]2 years ago
6 0
65/80 can be reduced to 13/16.
kotegsom [21]2 years ago
5 0
So, it says that there are 80 M&M candies in a bowl. 15 are orange, so that means the others aren't orange. So, then you would do (the total number of  M&M candies in the bowl)-(the number of orange M&M candies)=The number of M&M candies that are not orange. So, 80-15=65.
So, they are 65/80 in the bowl that aren't orange. But we aren't done yet. We need to find the lowest term for 65/80. First, we'll need to find what can go into 65 and 80 evenly without leaving a remainder. Yes, you guessed it, five can go into 65 and 80 without leaving a remainder. So, 65 divided by 5=13 and 80 divided by 5=16. So, your final answer is 13/16. 
13/16 is the final answer. This is the lowest possible term for the number pf candies that aren't orange.
65/80=13/16
13/16 are the number of M&M candies that aren't orange.
Hope I helped.
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2 years ago
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Natalija [7]

Answer:

a_{10}=\dfrac{1}{128}

Step-by-step explanation:

In the geometric series:

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The nth term of the geometric sequence can be calculated using formula

a_n=a_1\cdot r^{n-1}

In your case, n = 10, then

a_{10}\\ \\=4\cdot \left(\dfrac{1}{2}\right)^{10-1}\\ \\=4\cdot \left(\dfrac{1}{2}\right)^9\\ \\=2^2\cdot \dfrac{1}{2^9}\\ \\=\dfrac{1}{2^{9-2}}\\ \\=\dfrac{1}{2^7}\\ \\=\dfrac{1}{128}

8 0
2 years ago
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Jet001 [13]

Answer:

The square cake is has a larger area by about 40.73 square inches

Step-by-step explanation:

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The square cake has an area of 81 sq inches,   ( length x width = Area, the

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The round cake has an area of 16π, which is about 50.27 square inches

  (A = πr², here r is 4, radius is half the diameter)

81 - 16π =  81 - 50.27 =  40.73 square inches

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Answer:

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