Answer: the mode is 67.2
Step-by-step explanation:
Given that;
Data Frequency
30 - 34 1
35 - 39 0
40 - 44 3
45 - 49 7
50 - 54 5
55 - 59 10
60 - 64 10
65 - 69 21
70 - 74 12
Mode = ?
we know that mode is the number that has the highest number of appearance of frequency, so in this case, the data group that has the highest frequency (21) is 65 - 69
Lower class boundary of the modal group; L = 65
Frequency of the group before the modal group; Fm-1 = 10
Frequency of the modal group; Fm = 21
Frequency of the group after the modal group; Fm+1 = 12
Group width; G = 4
Now using the formula
Mode = L + [ (Fm - Fm-1) / ( (Fm - Fm-1) + (Fm - Fm+1) ) ] × W
so we substitute
Mode = 65 + [ (21 - 10) / ( (21 - 10) + (21 - 12) ) ] × 4
= 65 + [ 11 / 20] × 4
= 65 + 2.2
= 67.2
Therefore the mode is 67.2
Answer:
The answer to this question is
Angle at C is 35
Angle at D is 81
Angle at E is 64
because y=6
I did the problem and i got that they are both equal because they are touching each other
Answer: It packages 160 packages in 4 minutes.
Step-by-step explanation: Have a great day
Answer:
17 rows
Step-by-step explanation:
We know that f(x) = 2x² - 10x models the total number of spaces and x models the number of rows.
Since we are given the total number of spaces of 408. We let f(x) = 408
2x² - 10x = 408
Now we solve as a quadratic, subtract 408 to both sides
2x² - 10x - 408 = 0
Divide 2 on both sides
x² - 5x - 204 = 0
We look for terms that multiply to -204 and add to -5.
Those terms are -17 and 12
x² - 17x + 12x - 204 = 0
x(x-17) + 12(x-17)
(x+12)(x-17)
x = -12 x = 17
We can not have -12 rows but we can have 17 rows.
17 rows is the answer.
