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Vika [28.1K]
2 years ago
6

6. The pressure exerted on the walls of a container by a gas enclosed within it is directly proportional to

Mathematics
1 answer:
d1i1m1o1n [39]2 years ago
3 0

Answer: 5.18 pounds

Step-by-step explanation:

Given: The pressure exerted on the walls of a container by a gas enclosed within it is directly proportional to  the temperature of the gas.

Let 'p' denote the pressure exerted on the walls and 't' denotes  temperature of the gas.

Then the equation is given by :-

p=ct, where c is the proportionality constant.

Also, the pressure is 6 pounds per square inch when the temperature is 440° F.

\Rightarrow\ 6=440c\\\\\Rightarrow\ c=\dfrac{6}{440}=\dfrac{3}{220}

Then, the final equation to calculate pressure becomes :-

p=\dfrac{3}{220}t

Now, the pressure exerted when the temperature of the gas is 380°F is given by :-

p=\dfrac{3}{220}\times380=5.181818\approx5.18\text{ pounds}

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Read 2 more answers
P(x)= 3x^3-5x^2-14x-4
nexus9112 [7]
   
\displaystyle\\
P(x)=3x^3-5x^2-14x-4\\\\
D_{-4}=\{-4;~-2;~\underline{\bf -1};~1;~2;~4\}\\\\
\text{We observe that } \frac{-1}{3} \text{ is a solution of the equation:}\\
3x^3-5x^2-14x-4=0\\\\


\displaystyle\\
\text{Verification}\\\\
3x^3-5x^2-14x-4=\\\\
=3\times\Big(-\frac{1}{3}\Big)^3-5\times\Big(-\frac{1}{3}\Big)^2-14\times\Big(-\frac{1}{3}\Big)-4=\\\\
=-\frac{1}{9}-\frac{5}{9}+\frac{14}{3}-4=\\\\
=-\frac{6}{9}+\frac{14}{3}-4=\\\\
=-\frac{6}{9}+\frac{42}{9}- \frac{4\times 9}{9}=\\\\
 =-\frac{6}{9}+\frac{42}{9}- \frac{36}{9}= \frac{42-6-36}{9}=\frac{42-42}{9}=\frac{0}{9}=0\\\\
\Longrightarrow~~~P(x)~\vdots~\Big(x+ \frac{1}{3}\Big)\\\\
\Longrightarrow~~~P(x)~\vdots~(3x+1)


\displaystyle\\
3x^3-5x^2-14x-4=0\\
~~~~~-5x^2 = x^2 - 6x^2\\
~~~~~-14x =-2x-12x \\
3x^3+x^2 - 6x^2-2x-12x-4=0\\
x^2(3x+1)-2x(3x+1) -4(3x+1)=0\\
(3x+1)(x^2-2x -4)=0\\\\
\text{Solve: } x^2-2x -4=0\\\\
x_{12}= \frac{-b\pm  \sqrt{b^2-4ac}}{2a}=\\\\=\frac{2\pm  \sqrt{4+16}}{2}=\frac{2\pm  \sqrt{20}}{2}=\frac{2\pm  2\sqrt{5}}{2}=1\pm\sqrt{5}\\\\
x_1 =1+\sqrt{5}\\
x_2 =1-\sqrt{5}\\
\Longrightarrow P(x)= 3x^3-5x^2-14x-4 =\boxed{(3x+1)(x-1-\sqrt{5})(x-1+\sqrt{5})}



7 0
2 years ago
The length of a rectangle is 6 inches longer than it’s width what are the possible widths if the area of the rectangle is at lea
stealth61 [152]

Let the width = x

length = x + 6

(x + 6) * x = 667

Simplify

x² + 6 = 667

x² + 6 (-6) = 667 (-6)

x² = 661

√x² = √661

x = √661

x = 25.71 (rounded)

25.71 in. is your width

hope this helps

6 0
3 years ago
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