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ratelena [41]
3 years ago
13

Help me pls pls pls

Mathematics
1 answer:
-BARSIC- [3]3 years ago
5 0

Answer:

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Determine the y-intercept and slope and then write the equation for this table.*​
Novosadov [1.4K]

Answer:

The y-intercept is 15 and the slope is 5.5

y=5.5x+15

Step-by-step explanation:

4 0
3 years ago
I need help with this please
Hoochie [10]

Answer:

B. 15

Step-by-step explanation:

6 x 5 = 30

1/2 or 30 is 15

6 0
3 years ago
For a population with u=100 and a=20, what is the z-score that corresponds to x=90?
max2010maxim [7]
I guess that u = μ & that a=σ. If so:

μ =100 & that σ =20 & x=20

Z score = (x-μ) / σ  ==> Z score = (90-100)/20 ==> Z = - 0.5
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3 years ago
Remainders and leftlover. Is the same?
horrorfan [7]
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8 0
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Consider the probabilities of people taking pregnancy tests. Assume that the true probability of pregnancy for all people who ta
Valentin [98]

Using conditional probability, it is found that there is a 0.8462 = 84.62% probability that a woman who gets a positive test result is truly pregnant.

<h3>What is Conditional Probability?</h3>

Conditional probability is the probability of one event happening, considering a previous event. The formula is:

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

  • P(B|A) is the probability of event B happening, given that A happened.
  • P(A \cap B) is the probability of both A and B happening.
  • P(A) is the probability of A happening.

In this problem, the events are:

  • Event A: Positive test result.
  • Event B: Pregnant.

The probability of a positive test result is composed by:

  • 99% of 10%(truly pregnant).
  • 2% of 90%(not pregnant).

Hence:

P(A) = 0.99(0.1) + 0.02(0.9) = 0.117

The probability of both a positive test result and pregnancy is:

P(A \cap B) = 0.99(0.1)

Hence, the conditional probability is:

P(B|A) = \frac{0.99(0.1)}{0.117} = 0.8462

0.8462 = 84.62% probability that a woman who gets a positive test result is truly pregnant.

You can learn more about conditional probability at brainly.com/question/14398287

7 0
2 years ago
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