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4 years ago

Algebra 2 please help

Mathematics

1 answer:

gtnhenbr [62]4 years ago

3 0

Answer:

x > 0

Step-by-step explanation:

Division by zero is not defined. Therefore, x must be greater than zero. Also: The square root function is defined only for x greater than zero or equal to zero. Together these restrictions tell us that the domain is (0, infinity ).

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The temperature falls from 0 degrees to -12.4 degrees in

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The temperature falls from 0 degrees to -12.4

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3 years ago

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4 years ago

Solve for v: -4(v - 2) + 3 > -3(v + 9)

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Answer:

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3 years ago

Read 2 more answers

Can someone explain to me how to find the vertex form of this equation? y= -x^2 + 12x-4

AVprozaik [17]

<u>ANSWER: </u>

The vertex of given equation $y=-x^{2}+12 x-4$ is (6, 32).

<u>SOLUTION: </u>

Given, quadratic equation is $y=-x^{2}+12 x-4$

Above equation is a parabola and we need to find the vertex of that parabola. We know that, general form of the parabola is $y=a(x-h)^{2}+k$

Where, (h, k) is the vertex.

So, let us convert the given equation in parabolic equation.

$\begin{array}{l}{y=-x^{2}+12 x-4} \\ {y=-\left(x^{2}-12 x+4\right)} \\ {y=-\left(x^{2}-(2)(x)(6)+6^{2}-6^{2}+4\right)} \\ {\left.y=-\left((x-6)^{2}-36+4\right)\right)} \\ {y=-(x-6)^{2}+32}\end{array}$

Now, by comparing above equation with general form,

h = 6, k = 32 and a = -1.

Hence, the vertex of given equation is (6, 32).

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3 years ago

Help Me With This Question

Anastaziya [24]

Cant really see it................

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3 years ago