Solve for v: -4(v - 2) + 3 > -3(v + 9)

Mathematics

2 answers:

vitfil [10]3 years ago

7 0

Answer:

-4v + 8 > -3v - 9

-v + 8 > -9

-v > -17

v < 17

Harrizon [31]3 years ago

7 0

Answer:

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Step-by-step explanation:

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P=-3w+9 tell me the steps I already have the steps

anastassius [24]

You're solving for w for I assume.

P= -3w+9, put -3w on the left side and P on the right side.
3w= -P+9, divide both sides by 3.
w= -P+9 over 3.
w= -P over 3 plus 9 over 3.
(Final Answer):
w= -p over 3 plus 3.

Hope this helps.

4 0

3 years ago

How many ways are there to select 12 countries in the United Nations to serve on a council if 5 are selected from a block of 45,

melomori [17]

Answer:

There are 436937109262510348800 ways to selected 12 countries.

Step-by-step explanation:

Let $x_1, x_2, x_3, x_4,x_5$ the countries selected from the block of 45. For $x_1$ there are 45 options of countries to select. For $x_2$ there are 44 options of countries to select because there can be no repeated countries. With the same reasoning, for $x_3$ there are 43 options, for $x_4$ there are 42 options and for $x_5$ there are 41 options.

Let $x_6, x_7, x_8, x_9$ the countries selected from the block of 57 countries. For $x_6$ there are 57 options of countries to select. For $x_7$ there are 56 options of countries to select because there can be no repeated countries. With the same reasoning, for $x_8$ there are 55 options and for $x_9$ there are 54 options.

Let $x_{10}, x_{11}, x_{12}$ the countries selected from the block of 69 remain countries. For $x_{10}$ there are 69 options of countries to select. For $x_{11}$ there are 68 options of countries to select because there can be no repeated countries and for $x_{12}$ there are 67 options.