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forsale [732]
2 years ago
10

PLZ HELP QUICK

Mathematics
1 answer:
stellarik [79]2 years ago
5 0

Answer:

B

Step-by-step explanation:

Adams headed the Commission that negotiated the Treaty of Ghent in 1814, which ended the War of 1812 with Great Britain.

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Solve the proportion using equivalent ratios. Explain the steps you used to solve the proportion, and include the answer in your
NikAS [45]
10x=60
x=6
10/3=20/6
^^^^^^^^^^^^
7 0
2 years ago
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The table shows the distance Allison drove on one day of her vacation. Is the relationship between the distance and the time a p
Anuta_ua [19.1K]

Answer:

we conclude that the relationship between distance and time is NOT proportional.

Hence, she did not drive at a constant speed.

Step-by-step explanation:

We know that when 'y' varies directly with 'x', we get the equation

y ∝ x

y = kx

k = y/x

where 'k' is called the constant of proportionality.

In our case, the table shows the distance Allison drove on one day of her vacation.

Time (h)              1         2        3          4        5

Distance (mi)       55    100     165     280    250

using the equation

k = y/x

susbtitute y = 55, x = 1

k = 55/1 = 55

substitute y = 100, x = 2

k = y/x

k = 100 / 2 = 50

substitute y = 165, x = 3

k = y/x

k = 165 / 3 = 55

substitute y = 280, x = 4

k = y/x

k = 280 / 4 = 70

substitute y = 250, x = 5

k = y/x

k = 250 / 5 = 50

It is clear that the value of 'k' does not remain constant.

Therefore, we conclude that the relationship between distance and time is NOT proportional.

Hence, she did not drive at a constant speed.

6 0
3 years ago
Find the length of the curve y = 3/5x^5/3 - 3/4x^1/3 + 6 for 1 < = x < = 8. The length of the curve is . (Type an exact an
Mashutka [201]

Answer:

\sqrt\frac{387}{20}

Step-by-step explanation:

Arc Length =\int\limits^a_b {\sqrt{1+(\frac{dy}{dx})^2 } } \, dx

y=\dfrac{3}{5}x^{\frac{5}{3}}-  \dfrac{3}{4}x^{\frac{1}{3}}+6

\frac{dy}{dx} =x^{\frac{2}{3}}-\dfrac{1}{4}x^{-\frac{2}{3}}

1+(\frac{dy}{dx})^2 }=1+(x^{\frac{2}{3}}-\dfrac{1}{4}x^{-\frac{2}{3}})^2\\=1+(x^{\frac{4}{3}}-\dfrac{1}{2}+ \dfrac{1}{16}x^{-\frac{4}{3}})

=\dfrac{1}{2}+x^{\frac{4}{3}}+ \dfrac{1}{16}x^{-\frac{4}{3}}

For the Interval 1\leq x\leq 8

Length of the Curve =\int\limits^8_1 {\sqrt{\dfrac{1}{2}+x^{\frac{4}{3}}+ \dfrac{1}{16}x^{-\frac{4}{3}} } } \, dx\\

Using T1-Calculator

=\sqrt\frac{387}{20}

3 0
3 years ago
where p is the price (in dollars) and x is the number of units (in thousands). Find the average price p on the interval 40 ≤ x ≤
marusya05 [52]

THIS IS THE COMPLETE QUESTION BELOW

The demand equation for a product is p=90000/400+3x where p is the price (in dollars) and x is the number of units (in thousands). Find the average price p on the interval 40 ≤ x ≤ 50.

Answer

$168.27

Step by step Explanation

Given p=90000/400+3x

With the limits of 40 to 50

Then we need the integral in the form below to find the average price

1/(g-d)∫ⁿₐf(x)dx

Where n= 40 and a= 50, then if we substitute p and the limits then we integrate

1/(50-40)∫⁵⁰₄₀(90000/400+3x)

1/10∫⁵⁰₄₀(90000/400+3x)

If we perform some factorization we have

90000/(10)(3)∫3dx/(400+3x)

3000[ln400+3x]₄₀⁵⁰

Then let substitute the upper and lower limits we have

3000[ln400+3(50)]-ln[400+3(40]

30000[ln550-ln520]

3000[6.3099×6.254]

3000[0.056]

=168.27

the average price p on the interval 40 ≤ x ≤ 50 is

=$168.27

8 0
3 years ago
The product of two numbers is −72. One of the factors is −9, what is the other factor?
frez [133]
The other factor is eight because 9 multiplied by eight is 72 and a negative times a positive is a negative
4 0
2 years ago
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