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6x – 3y = -33<br> - 6x + 5y = 31

Readme [11.4K]

Answer:

check online for more information

4 0

2 years ago

You can walk 112 miles in 12 hour. <br><br> What is your average speed?

pishuonlain [190]

Hi,

You can walk 9.3 miles per hour.

<em>Hope this helps!</em>

8 0

3 years ago

Read 2 more answers

2. how is inquizitive graded? if you answer a question incorrectly on your first attempt, you will lose points.

ser-zykov [4K]

The more questions you successfully answer on your first attempt, the more points you will receive. The more times you attempt a question, the more points you'll lose if you get it wrong.

Inquizitive is graded in following ways -

Reach a Target Score set by your instructor; Provide a Correct Answer; Respond to a minimum number of questions.
The incorrect response is to simultaneously shove five large marshmallows in your mouth.
In InQuizitive, points are earned by responding to questions.
You use the Question confidence slider (to the right if using a computer or at the bottom for Smartphterm-2one users) to calculate how many points you can earn or lose on each question.
In order to receive a mark for the exercise, you must respond to a certain number of questions.
You must achieve a predetermined goal Score in order to receive a perfect score (100%) on the activity.

To learn more about Inquizitive from given link

brainly.com/question/14317711

#SPJ4

8 0

2 years ago

A bag contains only red and blue marbles. Yasmine takes one marble at random from the bag. The probability that she takes a red

mamaluj [8]

Let red marbles = X.

The probability is 1 out of 5, written as 1/5

1/5 in terms of red marbles is equal to the number of red marbles divided by 5x, where 5x is the total number of marbles.

1/5 = x/5x

Now you have 5x total marbles, x red and 4x blue.

Add 5 more red and the new probability is:

(x+5)/(5x+5) = 1/3

Simplify:

3x+15 = 5x+5

Now solve for x:

Subtract 3x from both sides:

15 = 2x +5

Subtract 5 from each side:

2x = 10

Divide both sides by 2:

x = 10/2

X = 5

There were originally 5 red marbles.

5 0

3 years ago

10. A manufacturer wanted to know if more coupons would be redeemed if they were mailed to the

Mandarinka [93]

Using the t-distribution, it is found that the data does not provide convincing evidence that the mean number is greater when the coupons were addressed to a female.

<h3>What are the hypothesis tested?</h3>

At the null hypothesis, it is tested if there is no difference, that is, the mean is of 0, hence:

$H_0: \mu = 0$

At the alternative hypothesis, it is tested if the mean number is greater for females, that is, the mean is greater than 0, hence:

$H_1: \mu > 0$

<h3>What is the test statistic?</h3>

The test statistic is given by:

$t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}$

The parameters are:

$\overline{x}$ is the sample mean.

$\mu$ is the value tested at the null hypothesis.

s is the standard deviation of the sample.

n is the sample size.

In this problem, the parameters are given as follows:

$\overline{x} = 1.5, \mu = 0, s = 4.75, n = 50$ .

Hence, the test statistic is given by:

$t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}$

$t = \frac{1.5 - 0}{\frac{4.75}{\sqrt{50}}}$

t = 2.23

<h3>What is the conclusion?</h3>

Considering a <em>right-tailed test</em>, as we are testing if the mean is greater than a value, with a <em>significance level of 0.01 and 50 - 1 = 49 df</em>, the critical value is given by $t^{\ast} = 2.4$ .

Since the test statistic is less than the critical value for the right-tailed test, the data does not provide convincing evidence that the mean number is greater when the coupons were addressed to a female.

More can be learned about the t-distribution at brainly.com/question/26454209

5 0

2 years ago