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Ilia_Sergeevich [38]

3 years ago

11

Can someone get a ruler or tape measurer or something and measure your forearm and left foot? It is for a math assignment cause

my friends said no.
I need this by 8 in the morning eastern time
I will make brainliest

1 answer:

Alenkinab [10]3 years ago

4 0

Answer:

Yes as long as you can measure in inches or centimeters.

Step-by-step explanation:

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Eric was rock climbing. At one point, he stopped and climbed straight down 2\dfrac{1}{2}2

nikitadnepr [17]

The equation that matches the given situation is $-2\frac{1}{2}+6\frac{3}{4}=?$ . So, after two moves, Eric's elevation changed $4\frac{1}{4}$ meters above.

We know that in mathematics, subtraction means removing something from a group or a number of things. What is left in the group gets smaller when we subtract. The minuend is the first element we use. The subtrahend is the part that is being removed. The difference is the portion that remains after subtraction.

Assume that "negative" means climbing down and "positive" means climbing up. We must locate the elevation change in this area.

Given that Eric climbed straight down $2\frac{1}{2}$ meters. So we can write $-2\frac{1}{2}$ .

Again Eric climbed straight up $6\frac{3}{4}$ meters. So, we can write $6\frac{3}{4}$ .

Then the change = $-2\frac{1}{2}+6\frac{3}{4}$

= $-\frac{(2*2+1)}{2}+\frac{6*4+3}{4}$

= $-\frac{5}{2} +\frac{27}{4}$

= $\frac{-(5*2)+27}{4}$

= $\frac{-10+27}{4}$

= $\frac{17}{4}$

= $\frac{4*4+1}{4}$

= $4\frac{1}{4}$

Therefore, the equation that matches the given situation is $-2\frac{1}{2}+6\frac{3}{4}=?$ . So, after two moves, Eric's elevation changed $4\frac{1}{4}$ meters above.

Learn more about subtraction here -

brainly.com/question/24116578

#SPJ10

7 0

2 years ago

3x+1 = 5x-9. what is the value of x?

krok68 [10]

X=5.
Explanation:
Take 3x+1=5x-9 and subtract 1 from both sides.
Now you have 3x=5x-10, Subtract 5x from both sides to get -2x= -10
Now divide both sides by -2 and you have x=5 :).

3 0

3 years ago

Read 2 more answers

A student in Greece discovers a pottery bowl that contains 65% of its original amount of C-14

stira [4]

There isn't enough information to answer

4 0

4 years ago

A rectangular swimming pool measures 50 meters in length and 25 meters in width. If the length in the scale drawing is 10 cm, wh

mash [69]

Answer:

The 25 m width of the actual swimming pool in the scale drawing is 5 cm

Step-by-step explanation:

The dimensions of the actual swimming pool given are

Length = 50 meters

Width = 25 meters

The length of the swimming pool on the scale drawing = 10 cm

The scale of the scale drawing is therefore;

10 cm on the scale drawing is equivalent to 50 meters of the actual swimming pool

Which gives;

10 cm:50 m

However, 50 m = 5,000 cm, therefore;

10 cm:5,000 cm or 10 : 5,000

Which is 10 to 5000 or 10/10 to 5000/10 = 1 to 500

The scale of the scale drawing is 1 to 500

or 1 cm of the scale drawing = 5 meters of the actual swimming pool

Therefore, the width of 25 meters of the actual swimming pool can be given as follows;

5 m = 1 cm

1 m = 1 cm/5

25 m = 25× 1 m = 25 × 1 cm/5 = 5 cm

Therefore, the 25 m width of the actual swimming pool in the scale drawing = 5 cm.

5 0

4 years ago

Jeremy wants to determine the number of solutions for the equation below without actually solving the equation.

Degger [83]

Answer:

1 solution

Step-by-step explanation:

Jeremy can simplify the equation enough to determine if the x-coefficient on one side of the equation is the same or different from the x-coefficient on the other side. Here, that simplification is ...

-3x -3 +3x = -3x +3 +3

We see that the x-coefficient on the left is 0; on the right, it is -3. These values are different, so there is one solution.

__

In the attached, the left-side expression is called y1; the right-side expression is called y2. The two expressions are equal where the lines they represent intersect. That point of intersection is x=3. (For that value of x, both sides of the equation have a value of -3.)

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<em>Additional comment</em>

If the equation's x-coefficients were the same, we'd have to look at the constants. If they're the same, there are an infinite number of solutions. If they are different, there are no solutions.

8 0

3 years ago

Read 2 more answers