The answer is![\left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] x^{2} x^{2} \sqrt[n]{x} \sqrt[n]{x} \pi \pi](https://tex.z-dn.net/?f=%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%262%263%5C%5C4%265%266%5C%5C7%268%269%5Cend%7Barray%7D%5Cright%5D%20%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%262%263%5C%5C4%265%266%5C%5C7%268%269%5Cend%7Barray%7D%5Cright%5D%20%20x%5E%7B2%7D%20%20x%5E%7B2%7D%20%20%5Csqrt%5Bn%5D%7Bx%7D%20%20%5Csqrt%5Bn%5D%7Bx%7D%20%20%5Cpi%20%20%5Cpi%20)
Can someone get a ruler or tape measurer or something and measure your forearm and left foot? It is for a math assignment cause
1 answer:
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This is a 30-60-90 triangle. The short leg is given to us as 5
The long leg is equal to sqrt(3) times the short leg
long leg = sqrt(3)*(short leg)
long leg = sqrt(3)*5
long leg = 5*sqrt(3)
The base is 5. The height is 5*sqrt(3)
b = 5
h = 5*sqrt(3)
Use this to find the area
A = b*h/2
A = 5*5*sqrt(3)/2
A = 25*sqrt(3)/2
which is the exact area in terms of a radical
You can write it out as
The long leg is equal to sqrt(3) times the short leg
long leg = sqrt(3)*(short leg)
long leg = sqrt(3)*5
long leg = 5*sqrt(3)
The base is 5. The height is 5*sqrt(3)
b = 5
h = 5*sqrt(3)
Use this to find the area
A = b*h/2
A = 5*5*sqrt(3)/2
A = 25*sqrt(3)/2
which is the exact area in terms of a radical
You can write it out as
The only solution for 
is 
, so it's either 
or 
.
Both
and 
are equal to 1, so the answer is .
Both
Answer:
5 units.
Step-by-step explanation: