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Ilia_Sergeevich [38]
3 years ago
11

Can someone get a ruler or tape measurer or something and measure your forearm and left foot? It is for a math assignment cause

my friends said no.
I need this by 8 in the morning eastern time
I will make brainliest
Mathematics
1 answer:
Alenkinab [10]3 years ago
4 0

Answer:

Yes as long as you can measure in inches or centimeters.

Step-by-step explanation:

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A report on consumer financial literacy summarized data from a representative sample of 1,664 adult Americans. Based on data fro
daser333 [38]

Answer:

a. The 95% confidence interval for the proportion of all adult Americans who would give themselves a grade of A or B on their financial knowledge of personal finance is (0.54, 0.588). This means that we are 95% sure that the true proportion of all adult Americans who would give themselves a grade of A or B on their financial knowledge of personal finance is between these two bounds.

b. Because this confidence interval is entirely above 0.5, the interval is consistent with the statement that a majority of adult Americans would give themselves a grade of A or B.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

Sample of 1,664 adult Americans, 939 people in the sample would have given themselves a grade of A or B in personal finance.

This means that n = 1664, \pi = \frac{939}{1664} = 0.5643

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.5643 - 1.96\sqrt{\frac{0.5643*0.4357}{1644}} = 0.54

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.5643 + 1.96\sqrt{\frac{0.5643*0.4357}{1644}} = 0.588

The 95% confidence interval for the proportion of all adult Americans who would give themselves a grade of A or B on their financial knowledge of personal finance is (0.54, 0.588). This means that we are 95% sure that the true proportion of all adult Americans who would give themselves a grade of A or B on their financial knowledge of personal finance is between these two bounds.

(b) Is the confidence interval from part (a) consistent with the statement that a majority of adult Americans would give themselves a grade of A or B?

Yes, because the confidence interval is entirely above 0.5.

Because this confidence interval is entirely above 0.5, the interval is consistent with the statement that a majority of adult Americans would give themselves a grade of A or B.

8 0
2 years ago
Please help I don't know the median give an answer and explanation
morpeh [17]

Answer:

Median is the middle of the data set. For example this data set is 4, 6, 7, 9, 10. First you take out 4 and 10. The you take out 6 and 9 to get a median of 7. But if there is an even amount of numbers like in this data set, 1, 2, 4, 5. Then you take out 1 and 5 and then find the middle point in between 2 and 4 which is 3.

5 0
2 years ago
Alan bought a suit on sale for $208. This price was 35% less than the original price.
algol [13]

Answer:

280.8

Step-by-step explanation:

Since 100% is the full amount, and it is 35% off you add 35 to the 100. So you get 1.35. You finally multiply by 207 and get 280.8

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3 years ago
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