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dmitriy555 [2]
3 years ago
14

Solve y" + 5y' + 6y = 6t2 + 4t y(0) = y' (O) = 0

Mathematics
1 answer:
ollegr [7]3 years ago
7 0

Try the suggested solution (the answer is marked with red colour).

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Find the circumcenter of the triangle with vertices at A(2,4),<br> B(8, 4), and C(6, 10).
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2 years ago
( 7x + 1/2) + ( 7x - 7 and 1/2) Simplify
pishuonlain [190]

Answer:

The answer will be 7(2x - 1)

Step-by-step explanation:

1) Convert 7 and 1/2 to improper fraction. Use this rule: a b/c = ac + b/c

7x +  \frac{1}{2}  + 7x -  \frac{7 \times 2 + 1}{2}

2) Simplify 7 × 2 to 14 .

7x +  \frac{1}{2}  + 7x  -  \frac{14 + 1}{2}

3) Simplify 14 + 1 to 15.

7x +  \frac{1}{2}  + 7x -  \frac{15}{2}

4) Collect like terms.

(7x + 7x) + ( \frac{1}{2}  -  \frac{15}{2} )

5) simplify.

14x - 7

6) Factor out the common term 7.

7(2x - 1)

Therefor, the answer is 7( 2x - 1 ).

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2 years ago
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1st

Step-by-step explanation:

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Solve for x in this circle.
Katen [24]

Answer:

Step-by-step explanation:

7*(7 + x+1) = 6*(x + 5 + 6)       {Intersecting secant theorem}

7 *(x + 8) = 6*(x + 11)

Distributive property,

7x + 56   = 6x + 66

Subtract 56 from both sides

7x = 6x + 66 - 56

7x = 6x + 10

Subtract 6x from both sides

7x - 6x = 10

x = 10

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3 years ago
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