4 years ago

Solve y" + 5y' + 6y = 6t2 + 4t y(0) = y' (O) = 0

1 answer:

ollegr [7]4 years ago

7 0

Try the suggested solution (the answer is marked with red colour).

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aksik [14]

Answer:

D. $\frac{x-1}{x^2+3x+2}}$

Step-by-step explanation:

The given expression is;

$\frac{x}{x^2+3x+2}-\frac{1}{(x+2)(x+1)}$

This is the same as;

$\frac{x}{(x+2)(x+1)}-\frac{1}{(x+2)(x+1)}$

The denominators are the same.

Subtract the numerators and write one denominator;

$\frac{x-1}{(x+2)(x+1)}}$

Rewrite to get;

$\frac{x-1}{x^2+3x+2}}$

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3 years ago

Trava [24]

Answer: (5.9, 3.781)

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elixir [45]

The answer is

140 degree

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3 years ago

faust18 [17]

:) Hope this helps you to your question

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4 years ago

musickatia [10]

Answer:

true

Step-by-step explanation:

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3 years ago