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Maurinko [17]
3 years ago
14

PLEASE HELP! What is the area of triangle BCD in exact form? 35 points!

Mathematics
1 answer:
vampirchik [111]3 years ago
5 0
This is a 30-60-90 triangle. The short leg is given to us as 5 

The long leg is equal to sqrt(3) times the short leg

long leg = sqrt(3)*(short leg)
long leg = sqrt(3)*5
long leg = 5*sqrt(3)

The base is 5. The height is 5*sqrt(3)
b = 5
h = 5*sqrt(3)

Use this to find the area
A = b*h/2
A = 5*5*sqrt(3)/2
A = 25*sqrt(3)/2
which is the exact area in terms of a radical

You can write it out as \frac{25\sqrt{3}}{2}
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2 years ago
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Answer:

CD = √11 and CE = √11

Step-by-step explanation:

We know that m∠D is 45° (by using the sum of interior angles in a triangle) so therefore, ΔDCE is a 45 - 45 - 90 triangle (the 45, 45, and 90 refer to the angle measures). The ratio of sides in a 45 - 45 - 90 triangle is 1 : 1 : √2 where the 1s are the sides and the √2 is the hypotenuse. We need to solve for x in x : x : √22. If you notice that √22 = √2 * √11, we can use this to find x, therefore, x = 1 * √11 = √11 so CD = √11 and CE = √11.

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