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3 years ago

Estimate then solve using the standard algorithm 24 X 2.31 (I think it's 55.44 but IDK)

Mathematics

1 answer:

Mnenie [13.5K]3 years ago

3 0

55.44

hope this helps, have a great day

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Lily plants 2 red rosebushes, 8 pink rosebushes, and 6 yellow rosebushes. What is the ratio of pink and red

andrey2020 [161]

Answer:

C. 10 : 16

Step-by-step explanation:

Attached below

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3 years ago

Which table represents a linear function

lesya692 [45]

Answer: B

Step-by-step explanation:

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2 years ago

PLZ HELP ME!<br> Directions up above the picture<br> **MATH (Algebra)

Vikentia [17]

Answer:

The answer to your question is t = 1.3 s

Step-by-step explanation:

Data

Equation h(t) = -4.9t² + v₀t + h₀

v₀ = 0 m/s

h₀ = 8 m

t = ?

h = 0 m

Process

1.- Substitute the values in the formula

0 = -4.9t² + 0t + 8

2.- Simplification

0 = -4.9t² + 8

3.- Solve for t

4.9t² = 8

t² = 8/4.9

t² = 1.63

4.- Result

t = 1.27 ≈ 1.3 s

6 0

3 years ago

Two different radioactive isotopes decay to 10% of their respective original amounts. Isotope A does this in 33 days, while isot

Andrews [41]

Answer:

The approximate difference in the half-lives of the isotopes is 66 days.

Step-by-step explanation:

The decay of an isotope is represented by the following differential equation:

$\frac{dm}{dt} = -\frac{t}{\tau}$

Where:

$m$ - Current mass of the isotope, measured in kilograms.

$t$ - Time, measured in days.

$\tau$ - Time constant, measured in days.

The solution of the differential equation is:

$m(t) = m_{o}\cdot e^{-\frac{t}{\tau} }$

Where $m_{o}$ is the initial mass of the isotope, measure in kilograms.

Now, the time constant is cleared:

$\ln \frac{m(t)}{m_{o}} = -\frac{t}{\tau}$

$\tau = -\frac{t}{\ln \frac{m(t)}{m_{o}} }$

The half-life of a isotope ( $t_{1/2}$ ) as a function of time constant is:

$t_{1/2} = \tau \cdot \ln2$

$t_{1/2} = -\left(\frac{t}{\ln\frac{m(t)}{m_{o}} }\right) \cdot \ln 2$

The half-life difference between isotope B and isotope A is:

$\Delta t_{1/2} = \left| -\left(\frac{t_{A}}{\ln \frac{m_{A}(t)}{m_{o,A}} } \right)\cdot \ln 2+\left(\frac{t_{B}}{\ln \frac{m_{B}(t)}{m_{o,B}} } \right)\cdot \ln 2\right|$

If $\frac{m_{A}(t)}{m_{o,A}} = \frac{m_{B}(t)}{m_{o,B}} = 0.9$ , $t_{A} = 33\,days$ and $t_{B} = 43\,days$ , the difference in the half-lives of the isotopes is: