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joja [24]
3 years ago
15

FREE BRAINLIEST!!!!!!

Mathematics
1 answer:
vivado [14]3 years ago
7 0

Let's solve the first inequality at first. So,

−2(x + 4) + 10 < x − 7

-2x- 8 + 10 < x - 7 By distribution property.

-2x + 2 < x - 7 Adding the like terms.

-2x < x - 7 - 2 Subtract 2 from each sides.

-2x < x - 9 By simplifying.

-2x - x < -9 Subtract x from each sides.

-3x < -9

-\frac{3x}{3}

Since we are dividing by negative 3. So, sign of inequality will get change.

So, x>3

Now the next inequality is,

−2x + 9 > 3(x + 8)

-2x + 9 > 3x + 24

-2x > 3x + 24 - 9

-2x > 3x + 15

-2x - 3x > 15

-5x >15

-\frac{5x}{-5} >\frac{15}{-5}

So, x <-3

Hence, the correct choice is x > 3 or x < −3.

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They are perpendicular because they have slopes that are opposite reciprocals of −2 and one half.

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A function is said to be an Even function if it follows f(-x) = f(x).

A function is said to be an Odd function if it follows f(-x) = -f(x).

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Given y = sin³x/cos³x and y = 1/sec³x

y = sin^3x/cos^3x\\f(x) = sin^3x/cos^3x\\f(-x) = sin^3(-x)/cos^3(-x)\\f(-x)= (sin(-x))^3/(cos(-x))^3\\f(-x)=(-sin(x))^3/(cos(x))^3\\f(-x)=-sin^3x/cos^3x\\f(-x)=-f(x)\\Odd\; function

y=1/sec^3x\\f(x)= 1/sec^3x\\f(x)=cos^3x\\f(-x)=cos^3(-x)\\f(-x)=(cos(-x))^3\\f(-x)=(cos\;x)^3\\f(-x)=cos^3x\\f(-x)=f(x)\\Even\; function

Hence, first function is Odd, second function is Even.

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