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muminat
3 years ago
5

Solve the inequality and graph its solution: 6n – 11 > 31

Mathematics
1 answer:
miss Akunina [59]3 years ago
5 0
<span>6n – 11 > 31
</span><span>6n  > 31 + 11
</span>6n  > 42
  n > 42/6
  n > 7
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‼️‼️‼️‼️‼️‼️‼️‼️‼️‼️‼️‼️Please please help! I’ve been waiting for 30 minutes and still no one has helped!
Alex777 [14]
PART ;

......Circle A.................
Circumference - 2 pi r
25.12 = 2pi(4)
25.12 = 8i
Divide both sides by 8!!
3.14=pi

...Circle B.....................
Circumference = 2 pi r
9.42 = 2pi(3/2)
9.42 = 3pi
Divide both sides by 3!!!
3.14 = pi

PART B

.............Circle A...............
A=pi r ^2
50.24 = pi(4)^2
50.24=16pi
Divide both sides by 16!!!
3.14=pi

.............Circle B.............
A=pi r^2
7.065=pi(3/2)^2
7.065= 9pi/4
Divide both sides by 9/4!!!
3.14=pi

PART C

They used exactly 3.14 for the value of pi in CIRCLE A and B to get the circumference and the area :D

I hope this makes sense!!! 
When I wrote 'pi', it was supposed to be the symbol for pi. 
5 0
3 years ago
Which equation represents a proportional relationship?
storchak [24]

Answer:

y = 4x + 1

Step-by-step explanation:

I'm sorry if i am wrong

7 0
3 years ago
Solve this and get 50 Points
Anvisha [2.4K]
Y=50-3.25X after 12 lunches it would have a value of 11$
4 0
3 years ago
Read 2 more answers
What is <img src="https://tex.z-dn.net/?f=3%5E%7Bx%7D%20%3D%20%5Cfrac%7B1%7D%7B9%7D" id="TexFormula1" title="3^{x} = \frac{1}{9}
Makovka662 [10]

~\hspace{7em}\textit{negative exponents} \\\\ a^{-n} \implies \cfrac{1}{a^n} ~\hspace{4.5em} a^n\implies \cfrac{1}{a^{-n}} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ 3^x=\cfrac{1}{9}\implies 3^x=\cfrac{1}{3^2}\implies 3^x=3^{-2}\implies x = -2

8 0
2 years ago
Complete this activity. Interest at the rates of 5%, 6%, and 8% is earned on investments of $13,000, $12,000, and $4,000 respect
zvonat [6]

The answer is 1690. First find the amount of interest by a single investment by multiplying the investment amount by the percent interest in decimal form. Then calculate the total by adding up all the products of investment times interest. Matrices will allow to multiply two things together and add the products up all at the same time. So we need to find the investment matrix and interest matrix.

Investment matrix A (transposed)            = (a1 a2 a3) = (13,000 12,000 4,000)

Interest Matrix B                                       = (b1 b2 b3) = (0.05 0.06 0.08)

Amount of interest earned                        = a1b1 + a2b2 + a3b3

Amount of interest earned                        = (0.05) (13,000) + (0.06) (12,000) +                                                                                  (0.08)(4,000)

Amount of interest earned                        = 1690

7 0
4 years ago
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