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sertanlavr [38]
3 years ago
8

Ellie is ordering hot dogs for her son's birthday party. Each hot dog cost $1.50. For orders smaller than a dozen hot dogs, ther

e is a $3 delivery charge. Is the cost proportional to the number of hot dogs ordered?
no links please
Mathematics
2 answers:
Juliette [100K]3 years ago
7 0

Answer:

No

Step-by-step explanation:

If the person only ordering one hotdog which is 1.50 dollars why should they have to pay 3 dollars

siniylev [52]3 years ago
7 0
No, the charge comes from delivering it because it’s too few to actually make them good money.
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soldier1979 [14.2K]
You plug in 2x + 4 into the y for the other equation (3x +y ) and solve for it
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3 years ago
Can you please solve and explain how
Karolina [17]

First, it would help to simplify each side more:

Left side: 36 + 3(4x - 9) = 36 + 12x - 27 = 12x + 9

Right side: c(2x + 1) + 25 = 2cx + c + 25

Write the simplified equation:

12x + 9 = 2cx + c + 25

Usually when there is no solution, the coefficients of the variable on both sides are the same, so we can make the coefficient if x on the right side into 12:

2cx >>> 12x

Then, c must equal 6 to make this true.

The answer is choice (C).

6 0
3 years ago
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I think the answer is r=8..
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3 years ago
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velikii [3]

Answer:

32

Step-by-step explanation:

Step 1: Define

f(x) = 3x² - 5x - 4

g(x) = -4x - 12

Step 2: Find f(g(x))

f(g(x)) = 3(-4x - 12)² - 5(-4x - 12) - 4

f(g(x)) = 3(16x² + 96x + 144) + 20x + 60 + 4

f(g(x)) = 48x² + 288x + 432 + 20x + 64

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Step 3: Find f(g(-4))

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f(g(-4)) = 48(16) - 1232 + 496

f(g(-4)) = 768 - 736

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3 0
3 years ago
A researcher is going to estimate the average typing speed of students of a college. He selects a random sample of 20 students a
Stella [2.4K]

Answer:

The margin of error of the 90% confidence interval of a student's average typing speed is of 1.933 wpm.

Step-by-step explanation:

We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 20 - 1 = 19

90% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 19 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.9}{2} = 0.95. So we have T = 1.7291

The margin of error is:

M = T\frac{s}{\sqrt{n}}

In which s is the standard deviation of the sample and n is the size of the sample. For this question, we have s = 5, n = 20. So

M = T\frac{s}{\sqrt{n}}

M = 1.7291\frac{5}{\sqrt{20}}

M = 1.933

The margin of error of the 90% confidence interval of a student's average typing speed is of 1.933 wpm.

8 0
3 years ago
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