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3 years ago

Help ASAP! And explain!

Mathematics

1 answer:

stich3 [128]3 years ago

4 0

Answer:

Option (2)

Step-by-step explanation:

Given:

AC is an angle bisector of ∠DAB and ∠DAB

m∠BCA ≅ m∠DCA

m∠BAC ≅ m∠DAC

To Prove:

ΔABC ≅ ΔADC

Solution:

Statements Reasons

1). m∠BCA ≅ m∠DCA 1). Given

2). m∠BAC ≅ m∠DAC 2). Given

3). AC ≅ AC 3). Reflexive property

4). ΔABC ≅ ΔADC 4). ASA property of congruence

Therefore, Option (2) will be the correct option.

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What multiplies to 378 and adds to -51

Oliga [24]

Your answer would be -9 & -42.

Here's why ...
(-9)*(-42) A negative times a negative equals a positive (378).
Now, -9-42=-51 & you add these because you have two negatives.

Hope this makes sense & helps you ! (:

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Quick algebra 1 question for 50 points! <br><br><br> Only answer if you know the answer, Tysm!

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$revenue = selling \: price \times quantity \: sold$

$m(t) = 3t$

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2 years ago

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Solve: <br>x + y = 7<br>3x - 2y = 11<br><br>By using Substituting method.

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$\large\underline{\sf{Solution-}}$

$\sf \longmapsto x + y = 7 \: \: - - - (i)$

$\sf \longmapsto 3x - 2y = 11 \: \: - - - (ii)$

<u>By first equation,</u>

$\sf \longmapsto x + y = 7$

$\sf \longmapsto x = 7 - y$

<u>Now, we can find the original value of y.</u>

$\sf \longmapsto 3x - 2y = 11$

$\sf \longmapsto 3(7 - y) - 2y = 11$

$\sf \longmapsto 21 - 3y - 2y = 11$

$\sf \longmapsto 21 - 5y = 11$

$\sf \longmapsto - 5y = 11 - 21$

$\sf \longmapsto - 5y = - 10$

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$\sf \longmapsto y = 2$

<u>Now, we can find the original value of x.</u>

$\sf \longmapsto x + y = 7$

$\sf \longmapsto x + 2 = 7$

$\sf \longmapsto x = 7 - 2$

$\sf \longmapsto x = 5$

Therefore, the values of x and y are 5 and 2 respectively.

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3 years ago

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3 years ago

A rocket is launched at 85 ft./s from a launch pad that’s 28 feet above the ground. which equation can be used to determine the

3241004551 [841]

Answer:

$h(t)=-16t^2+85t+28$ is equation of height of rocket.

Option D is correct.

Step-by-step explanation:

Given: A rocket is launched with speed 85 ft/s from a height 28 feet.

Launching a rocket follows the path of parabola. The equation of rocket should be parabolic.

Parabolic equation of rocket is

Formula: $h(t)=\dfrac{1}2gt^2+v_0t+h_0$

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v ⇒ Initial velocity ( $v_0=85\ ft/s$ )

h ⇒ Initial height ( $h_0=28\ feet$ )

h(t) ⇒ function of height at any time t

Substitute the given values into formula

$h(t)=\frac{1}{2}(-32)t^2+(85)t+28$

$h(t)=-16t^2+85t+28$

D is correct.

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4 years ago

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