Question

Given: ΔKLM, KL = LM = 13in, KM = 10in. Find: The area of ΔKLM.

Answer 1

Answer:

$60 in^{2}$

Step-by-step explanation:

We are given a ΔKLM, in which KL=LM=13 in and KM=10 in which means two sides of the given triangle are same and thus is an isosceles triangle.

Its median drawn from L to the KM will be altitude. Therefore, ΔKLN and ΔLMN are right triangles.

In ΔKLN, using the pythagoras property, we have

$13^{2}=5^{2}+LN^{2}$

$169-25=LN^{2}$

$\sqrt{144} =LN$

$12=LN$

Now, Area of triangle= 1/2×base×height

                                   =1/2×10×12

                                   =60 squared inches.