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Roman55 [17]
3 years ago
11

Which are considered regulatory agencies? Check all that apply. WHO PPO HMO CMS CDC NIOSH

Computers and Technology
2 answers:
NISA [10]3 years ago
4 0
I believe the answer is CDC but I could be wrong
tatuchka [14]3 years ago
4 0

Answer:

The answer to the given question is "CDC".

Explanation:

The term CDC stands for the Centers for Disease Control and Prevention. CDC is the United States' first national public health center. The main objective is to protect public health and safety in the United States and globally by monitoring and preventing disease, injury, and disability. and all option is not correct that can be given as:

WHO: The primary role of the WHO is to coordinate public health within the framework of the United Nations and guide stakeholders in response to global health.

PPO: It is a  Medical and health care provider of PPO that is referred to as preferred providers.

HMO: It is a health care organization (HMO) is a network or organization that provides coverage for a monthly or annual fee for health insurance.

CMS: It stands for Centers for Medicare & Medicaid Services. It is part of the U.S. Department of Health and Human Services.

NIOSH: It is the responsibility of the National Institute of Occupational Safety and Health to conduct research and make guidelines for work-related injury and disease prevention.

That's why the answer is "CDC"

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3 years ago
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3 years ago
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5 0
4 years ago
Read 2 more answers
1. Print out the string length of s1 2. Loop through characters in s2 with charAt() and display reversed string 3. Compare s2, s
konstantin123 [22]

Answer:

See explaination

Explanation:

public class StringLab9 {

public static void main(String args[]) {

char charArray[] = { 'C', 'O', 'S', 'C', ' ', '3', '3', '1', '7', ' ', 'O', 'O', ' ', 'C', 'l', 'a', 's', 's' };

String s1 = new String("Objected oriented programming language!");

String s2 = "COSC 3317 OO class class";

String s3 = new String(charArray);

// To do 1: print out the string length of s1

System.out.println(s1.length());

// To do 2: loop through characters in s2 with charAt and display reversed

// string

for (int i = s2.length() - 1; i >= 0; --i)

System.out.print(s2.charAt(i));

System.out.println();

// To do 3: compare s2, s3 with compareTo(), print out which string (s2 or s3)

// is

// greater than which string (s2 or s3), or equal, print the result out

if (s2.compareTo(s3) == 0)

System.out.println("They are equal");

else if (s2.compareTo(s3) > 0)

System.out.println("s2 is greater");

else

System.out.println("s3 is greater");

// To do 4: Use the regionMatches to compare s2 and s3 with case sensitivity of

// the first 8 characters.

// and print out the result (match or not) .

if (s2.substring(0, 8).compareTo(s3.substring(0, 8)) == 0)

System.out.println("They matched");

else

System.out.println("They DONT match");

// To do 5: Find the location of the first character 'g' in s1, print it out

int i;

for (i = 0; i < s2.length(); ++i)

if(s2.charAt(i)=='g')

break;

System.out.println("'g' is present at index " + i);

// To do 6: Find the last location of the substring "class" from s2, print it

// out

int index = 0, ans = 0;

String test = s2;

while (index != -1) {

ans = ans + index;

index = test.indexOf("class");

test = test.substring(index + 1, test.length());

}

System.out.println("Last location of class in s2 is: " + (ans + 1));

// To do 7: Extract a substring from index 4 up to, but not including 8 from

// s3, print it out

System.out.println(s3.substring(4, 8));

} // end main

} // end class StringLab9

7 0
3 years ago
If a 60 lb. load is placed on the platform, what will the pressure gauge reading be if the piston area is 5 sq.in? Give your ans
Doss [256]

Answer:

The pressure gauge reading will be;

12 psi

Explanation:

The question relates to relationship of pressure and area

The given parameters for the measurement are;

The weight of the load = 60 lb

The required area of the piston = 5 in.²

Pressure exerted by a force can be defined as follows;

Pressure =  \dfrac{Force}{Area}

The weight of the load = The force applied by the load

Therefore;

Pressure =  \dfrac{Force}{Area} = \dfrac{60 \ lb}{5 \ in.^2}  = 12\dfrac{lb}{in.^2} = 12 \ psi

The gauge reading will be 12 psi.

7 0
3 years ago
Read 2 more answers
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