3 years ago

What are the possible damages for a rectangle with 12 ft.²

Mathematics

1 answer:

yanalaym [24]3 years ago

6 0

The answer is 24 if I'm right

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Neptune is an average distance of 4.5 × 10^9 km from the Sun. Estimate the length of the Neptunian year using the fact that the

zlopas [31]

Answer:

164.32 earth year

Step-by-step explanation:

distance of Neptune, Rn = 4.5 x 10^9 km

distance of earth, Re = 1.5 x 10^8 km

time period of earth, Te = 1 year

let the time period of Neptune is Tn.

According to the Kepler's third law

T² ∝ R³

$\left ( \frac{T_{n}}{T_{e}} \right )^{2}=\left ( \frac{R_{n}}{R_{e}} \right )^{3}$

$\left ( \frac{T_{n}}{1} \right )^{2}=\left ( \frac{4.5\times10^{9}}}{1.5\times10^{8}}} \right )^{3}$

Tn = 164.32 earth years

Thus, the neptune year is equal to 164.32 earth year.

Step-by-step explanation:

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N is equal to 2 in the equasion

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Marc's workout consists of swimming and practicing yoga. While swimming he burns 7 calories per minute, and while practicing yog

Scorpion4ik [409]

Answer:

7x + 5y ≥ 400

Step-by-step explanation:

Given:

Swimming burns = 7 calories per minute

Yoga burns = 5 calories per minute

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Total minutes of yoga = y

Find:

Inequality

Computation:

7 calories per minute(Total minutes of swimming) + 5 (Total minutes of yoga) ≥ 400

7x + 5y ≥ 400

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4 years ago

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3 years ago