Answer: 0.067 litres of water
Step-by-step explanation:
The mode is:
Concentration of new solution = Moles of acid in original solution / (Volume of original solution + Volume of water added)
Assume volume of water added is w.
12 = 16 (0.2) / (0.2 + w)
(0.2 + w) * 12 = 3.2
0.2 + w = 3.2 / 12
w = (3.2 / 12) - 0.2
w = 0.067 litres of water
Answer:
Suppose that logb b = x.
bx = b (Use the definition of a logarithm.)
bx = b1
x = 1 (Use the common base property.)
So, logb b = 1.
Hi
5x²-x-4 = 0
Δ= (-1)² - 4*5*(-4)
Δ = 1 -4*-20
Δ = 1 +80
Δ = 81
√Δ= 9
as Δ ≥ 0 , so 2 solutions exist in R
S1 is : ( 1+9) /2*5 = 10/10 = 1
s2 = (1 -9)/2*5 = -8/10 = -4*2 /2*5 = -4/5
Corrects answers are A and D
Answer:
b
Step-by-step explanation:
