$3.00 x .05 = 15 cents
$3.00+ .15= $3.15
3.15 final answer
Answer:
First term (a) =8
Common difference (d)= t2-t1
=12-8
=4
Now, sum of first 31th term (tn31) =n/2{2a+(n-1)d}
= 31/2{2×8+(31-1)4}
=31/2{16+(30×4)
=31/2(16+120)
=31/2×126
=31×63
Step-by-step explanation:
Similarly use 19 as (n) for the 19th term
Answer:

Step-by-step explanation:

First, use PEMDAS to distribute the -2 to the parenthesis.

Combine like terms on the right side.

Now, you may either subtract the f's or the constants. I'll subtract the constants first, meaning I will add 10 to both sides.

Now subtract the 2f from both sides.

Divide both sides by 10.

Simplify.

Answer: 24
Yes (x-2) is a factor. There is a remainder.
Step-by-step explanation:
2³-8•2²+14•2-4
8-8•4+14•2-4
0•4+14•2-4
0+14•2-4
14•2-4
28-4
24
Hope this helps if so plz mark me brainly