Answer:
25 and 21 hours respectively
Step-by-step explanation:
Let the number of hours worked by each welder be x and y respectively.
They worked a total of 46 hours. This means :
x + y = 46 hours.......(I)
Now, given their hourly charges, since we have the total amount of money realized, we can make an equation out of it. This means:
34x + 39y = 1669........(ii)
We then solve both simultaneously. From I, x = 46 -y
We can substitute this into ii
34(46 -y) + 39y = 1669
1564 -34y + 39y = 1669
5y = 1669 - 1564
5y = 105
y = 105/5 = 21
x = 46 - y
x = 46 - 21 = 25 hours
The numbers of hours worked by the welders are 25 and 21 respectively
Answer:
I believe it is: 6n+8+7y+4m
Step-by-step explanation:
You can't do anything about the numbers with variables afterwards, so you just list those and you just add and subtract the numbers without variables. Since the top and bottom are the same, you just list it once. Sorry, not the best explanation. Please let me know if I am wrong. It's been a while since I had to any type of algebra.
Answer:
in neighbourhood q the total number of people in the nine families I higher than that in neighbourhood s because of we add up the number of people in the families in neighbourhood q we get a total of 35 yet we have a total of only 27 people in the nine families in neighbourhood s
hope that helps ❤