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hammer [34]
3 years ago
8

The equation of a plane in space is x + 3y + 2z = 6.. a.)Accurately sketch the plane on the set of axes, showing all your calcul

ations below.. b.)The three planes of the axes and the plane you have sketched create a triangular pyramid. Find the volume of this pyramid, showing the formula you are using and make a graph from your answer.
Mathematics
1 answer:
nlexa [21]3 years ago
4 0
In getting the value of X, Y and Z in the equations X+3Y+2Z = 6 you must first substitute the variables into 0 and came up with the value of X=6, Y=2, and Z =3. So the volume of this pyramid is computed using V=1/3AH and the volume is 9. i hope you are satisfied with my answer 
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Will Mark brainlest !please help. (The probabilty of germenating a new flower seed is found to be 0.92,if you sow a packet of 50
kipiarov [429]

Answer: 0. 92 = 92%

100% = 500

92% = 500 × 92/100 = 460

Step-by-step explanation:

3 0
3 years ago
Neil started a stamp collection with 12 stamps. Every week , he adds 4 more stamps to the collection. Which function? F represen
svlad2 [7]

Answer:

s=4w+12

Step-by-step explanation:

Let

s -----> the number of stamps

w ----> the number of weeks

we know that

The linear equation that represent this situation is

s=4w+12 ----> equation of the line into slope intercept form

where

the slope m is equal to m=4\ stamps/week

the y-intercept b is equal to b=12\ stamps ---> (the initial value)

7 0
3 years ago
The rectangular field is 120 yards long and 40 yards wide. How many square yards is it’s area?
lilavasa [31]

Answer:

4800 yards wide

Step-by-step explanation:

120 x 40=4800

3 0
3 years ago
EMERGENCY (NEED HEP NOW!!!)
diamong [38]

Answer:

x=-2.25,y=-2.25

Step-by-step explanation:

The given system is

4x - y =  - 9 \\ 3x - 3y = 0

We want to solve the system for x and y that makes the system true.

Let us multiply the first equation by 3 while maintaining the second equation:

12x -3 y =  - 27 \\ 3x - 3y = 0

Subtract the current second equation from the first one.

12x =  - 27

Divide through by 12:

x =  -  \frac{27}{12}  =  - 2.25

From the second equation we have:

3x = 3y

This implies that:

x = y =  - 2.25

8 0
3 years ago
Consider the following differential equation. x^2y' + xy = 3 (a) Show that every member of the family of functions y = (3ln(x) +
Veronika [31]

Answer:

Verified

y(x) = \frac{3Ln(x) + 3}{x}

y(x) = \frac{3Ln(x) + 3 - 3Ln(3)}{x}

Step-by-step explanation:

Question:-

- We are given the following non-homogeneous ODE as follows:

                           x^2y' +xy = 3

- A general solution to the above ODE is also given as:

                          y = \frac{3Ln(x) + C  }{x}

- We are to prove that every member of the family of curves defined by the above given function ( y ) is indeed a solution to the given ODE.

Solution:-

- To determine the validity of the solution we will first compute the first derivative of the given function ( y ) as follows. Apply the quotient rule.

                          y' = \frac{\frac{d}{dx}( 3Ln(x) + C ) . x - ( 3Ln(x) + C ) . \frac{d}{dx} (x)  }{x^2} \\\\y' = \frac{\frac{3}{x}.x - ( 3Ln(x) + C ).(1)}{x^2} \\\\y' = - \frac{3Ln(x) + C - 3}{x^2}

- Now we will plug in the evaluated first derivative ( y' ) and function ( y ) into the given ODE and prove that right hand side is equal to the left hand side of the equality as follows:

                          -\frac{3Ln(x) + C - 3}{x^2}.x^2 + \frac{3Ln(x) + C}{x}.x = 3\\\\-3Ln(x) - C + 3 + 3Ln(x) + C= 3\\\\3 = 3

- The equality holds true for all values of " C "; hence, the function ( y ) is the general solution to the given ODE.

- To determine the complete solution subjected to the initial conditions y (1) = 3. We would need the evaluate the value of constant ( C ) such that the solution ( y ) is satisfied as follows:

                         y( 1 ) = \frac{3Ln(1) + C }{1} = 3\\\\0 + C = 3, C = 3

- Therefore, the complete solution to the given ODE can be expressed as:

                        y ( x ) = \frac{3Ln(x) + 3 }{x}

- To determine the complete solution subjected to the initial conditions y (3) = 1. We would need the evaluate the value of constant ( C ) such that the solution ( y ) is satisfied as follows:

                         y(3) = \frac{3Ln(3) + C}{3} = 1\\\\y(3) = 3Ln(3) + C = 3\\\\C = 3 - 3Ln(3)

- Therefore, the complete solution to the given ODE can be expressed as:

                        y(x) = \frac{3Ln(x) + 3 - 3Ln(3)}{y}

                           

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6 0
3 years ago
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