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STALIN [3.7K]
3 years ago
11

-3 < 5c + 7 < 22 algebra

Mathematics
1 answer:
Alexus [3.1K]3 years ago
8 0

Answer:=

Solution: -2<c<3

Interval Notation: (-2,3)

Step-by-step explanation:

-3<5c+7<22

-3<5c+7  :  c>-2

5c+7<22 : c<3

combine the intervals

c>-2 and c<3

-2<c<3

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This last one I need help on too
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Answer:

x=\frac{3}{4}+i\frac{\sqrt{7}}{4},\:x=\frac{3}{4}-i\frac{\sqrt{7}}{4}

Step-by-step explanation:

simplify \frac{-3}{x-2} by putting the negative sign on the outside. \frac{2x}{x-1}-\frac{2x-5}{x^2-3x+2}=-\frac{3}{x-2}

find the LCM of the denominators. It is (x-1)(x-2). Multiply by the LCM:

\frac{2x}{x-1}\left(x-1\right)\left(x-2\right)-\frac{2x-5}{x^2-3x+2}\left(x-1\right)\left(x-2\right)=-\frac{3}{x-2}\left(x-1\right)\left(x-2\right)

Simplify:

2x\left(x-2\right)-\left(2x-5\right)=-3\left(x-1\right)

solve: x=\frac{3}{4}+i\frac{\sqrt{7}}{4},\:x=\frac{3}{4}-i\frac{\sqrt{7}}{4}

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