<span>4/12=3/9=2/6=1/3 </span>should be the right answer. (You have to reduce.)
Steps
I’m using elimination so I’m trying to get rid of y
To do that I multiply the first equation by 2 and the second by -3. Then solve
4x + 6x = 12
15x + -6x = -12
—————————
19x + 0 = 0
Divid by 19 to get x to one side. 0/19 is 0 so
X= 0
Plug that into an equation so 0 + 3y = 6
Divid by 3 and y = 2
Answer x = 0 y = 2
If a polynomial with real coefficient has a complex zero, the conjugate of that number will be a zero as well.
So, if 4-6i is a zero, 4+6i will be a zero as well
If -2+11i is a zero, -2-11i will be a zero as well
So, the zeroes are
Answer:
1)When subtract you will still get a negative number
