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777dan777 [17]
2 years ago
9

Angela's text messaging plan charges 30¢ for each message over 600 in addition to a $9 base charge. If

Mathematics
1 answer:
anyanavicka [17]2 years ago
5 0

answer: 692

Step-by-step explanation:

36.6 - 9 = 27.6

27.6/0.3 = 92

600 + 92 = 692 text messages

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Simplify 6x+(- 9)-9(5x+5)+x
Hatshy [7]

Answer:

Step-by-step explanation:

I've already answered this question.

4 0
3 years ago
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Which of the following describes a correct method for solving the equation below?
ladessa [460]
1: multiple both sides by 2
Ex:-7n+10=-32
2: subtract 10 from both sides
Ex: -7n=-42
3:divide both sides by -7 to get n alone
Ex: n=6
Answer is 6 and the process is elimination!
8 0
2 years ago
One factor of 7x2 + 33x – 10 is
stiv31 [10]

7x^{2} +33x-10=0

\implies 7x^{2} +35x-2x-10=0\\\implies7x(x+5)-2(x+5)=0\\\implies (7x-2)(x+5)=0

7x - 2 = 0\\\implies \boxed{\bold{x = \frac{2}{7} }}

x+5=0\\\implies \boxed{\bold{x=-5}}

6 0
3 years ago
(a) Describe a property specific to squares that is not a property specific to rectangles.
blondinia [14]

Answer:

Step-by-step explanation:

(a) A square has all the 4 sides being equal while a rectangle has four sides, with the opposite sides being parallel and the same length.

(b) The diagonals bisect the angles , the diagonals are perpendicular bisectors of each other

(c) A square has two pairs of parallel sides, four right angles, and all four sides are equal while the angles of a parallelogram are not right angles

(d) a rhombus can be a rectangle (if the angles of the rhombus are all 90 degrees), and a rectangle can be a rhombus (if the sides of the rectangle are all equal length). Opposite sides are parallel.

(e) a rhombus has two opposite internal angles of equal measure, a square has four right angles with equal measure

5 0
3 years ago
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What is the center of the hyperbola whose equation is (y+3)^2/81-(x-6)^2/89=1?
xxMikexx [17]

We have been given an equation of hyperbola \frac{(y+3)^2}{81}-\frac{(x-6)^2}{89}=1. We are asked to find the center of hyperbola.  

We know that standard equation of a vertical hyperbola is in form \frac{(y-k)^2}{b^2}-\frac{(x-h)^2}{a^2}=1, where point (h,k) represents center of hyperbola.

Upon comparing our given equation with standard vertical hyperbola, we can see that the value of h is 6.

To find the value of k, we need to rewrite our equation as:

\frac{(y-(-3))^2}{81}-\frac{(x-6)^2}{89}=1

Now we can see that value of k is -3. Therefore, the vertex of given hyperbola will be at point (6,-3) and option D is the correct choice.

6 0
3 years ago
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