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3 years ago

There were 8 judges at a gymnastics competition. Kathleen received these scores for her performance on the uneven parallel bars.

Mathematics

2 answers:

Korolek [52]3 years ago

6 0

Answer:

below

Step-by-step explanation:

mean : 8.8

The mean is the average, so you find it by adding all the numbers together and dividing by n, or how many numbers there are. For this, I added to get 70.4 and divided that by 8 (8 total scores).

70.4/8 = 8.8.

median : 8.85

The median is the middle of the data set, so you put the numbers in increasing order (lowest number to highest number) and then finding the middle of that set. For this set, since there is an even number of numbers (8), you have to find the middle by adding the two middle numbers and dividing by 2.

8.2, 8.7, 8.8, 8.8, 8.9, 8.9, 8.9, 9.2

The middle numbers are 8.8 and 8.9, so you add those together and divide by 2 to get 8.85.

mode : 8.9

The mode is just what number appears most often. Because 8.9 appears three times in this data set, more than any other number, the mode is 8.9.

b. The mean reflects a typical score because it is the average, and is used most often when someone is expressing a typical or "average" score. It is the score most people are likely to get, and as there are no outliers in this data set, it reflects a typical score for this data set. It is also the same as the mode, or most often score, in this data set.

oee [108]3 years ago

3 0

1) Put the numbers in order

8.2, 8.7, 8.8, 8.8, 8.9, 8.9, 8.9, 9.2

2) mean is average

70.4/8 = 8.8

3) Median is the middle number; if m = 2, then divide them by 2

17.7/2 = 8.85

4) Mode is most often

8.9 (3 times)

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I’m working on 3 and 4 only maybe if I can have some explanation so I can understand and do more of these next week.

guapka [62]

4.b.

Answer: See below.

Step-by-step explanation:

<h2>For the equation f(x) = 2x</h2>

3.a. f(6) means use x = 6 in the equation f(x) = 2x

so f(6) would be f(6)= 2(6)

f(6) = 12

3.b. f(-11) = 2(-11)

f(-11) = -22

3.c. f(2.75) = 2(2.75)

f(2.75) = 5.5

3.d. This is turned around. We are told f(x)=20, so what would x need to be for f(x) to be 20? Since f(x) = 2x, we can say 20 = 2x. Therefore x = 10

f(10) = 20

The rest of (3) are solved in the same fasion.h

<h2>For the equation f(x)= 5x+50</h2>

4.a. f(7) = 5(7)+50

f(7) = 85

4.b. f(-12)

f(-12) = 5*(-12)+50

f(-12) = -60

Continue in the same fashion for these types of problems.

7 0

2 years ago

Darren teaches a class of 25 students. He assigns homework 3 times a week, and each assignment consists of 12 problems. How many

kipiarov [429]

I think its 900
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6 0

3 years ago

Read 2 more answers

Falling object formula: h=-16t+s

vitfil [10]

Answer:

34.714 seconds

Step-by-step explanation:

According to the question we have:

Formula h = - 16t + s
h = 0
s = 555.427 ft
t = ?

Substitute the given values and solve for t:

0 = - 16t + 555.427
16t = 555.427
t = 555.427/16
t = 34.714

3 0

2 years ago

Can someone please help me with my maths question

DIA [1.3K]

Answer:

$a. \ \dfrac{625 \cdot m}{27 \cdot n^{11}}$

$b. \ \dfrac{x^{3 \cdot m - 2}}{y^{ 3 + n}}$

Step-by-step explanation:

The question relates with rules of indices

(a) The give expression is presented as follows;

$\dfrac{m^3 \times \left (n^{-2} \right )^4 \times (5 \cdot m)^4}{\left (3 \cdot m^2 \cdot n \right )^3}$

By expanding the expression, we get;

$\dfrac{m^3 \times n^{-8} \times 5^4 \times m^4}{\left 3^3 \times m^6 \times n^3}$

Collecting like terms gives;

$\dfrac{m^{(3 + 4 - 6)} \times 5^4}{ 3^3 \times n^{3 + 8}} = \dfrac{625 \cdot m}{27 \cdot n^{11}}$

$\dfrac{m^3 \times \left (n^{-2} \right )^4 \times (5 \cdot m)^4}{\left (3 \cdot m^2 \cdot n \right )^3}= \dfrac{625 \cdot m}{27 \cdot n^{11}}$

(b) The given expression is presented as follows;

$x^{3 \cdot m + 2} \times \left (y^{n - 1} \right )^3 \div (x \cdot y^n)^4$

Therefore, we get;

$x^{3 \cdot m + 2} \times \left (y^{n - 1} \right )^3 \times x^{-4} \times y^{-4 \cdot n}$

Collecting like terms gives;

$x^{3 \cdot m + 2 - 4} \times \left (y^{3 \cdot n - 3 -4 \cdot n}} \right ) = x^{3 \cdot m - 2} \times \left (y^{ - 3 -n}} \right ) = x^{3 \cdot m - 2} \div \left (y^{ 3 + n}} \right )$

$x^{3 \cdot m - 2} \div \left (y^{ 3 + n}} \right ) = \dfrac{x^{3 \cdot m - 2}}{y^{ 3 + n}}$

$x^{3 \cdot m + 2} \times \left (y^{n - 1} \right )^3 \times x^{-4} \times y^{-4 \cdot n} =\dfrac{x^{3 \cdot m - 2}}{y^{ 3 + n}}$

4 0

3 years ago

Sara put 7 boxes in her closet. Each box is for holding a different type of seashell. So far, there are 0 shells in each box. Ho

user100 [1]

Given that Sara put 7 boxes in her closet.

So number of boxes = 7

Then it says that each box is for holding a different type of seashell. So far, there are 0 shells in each box.

So the number of seashell in 1 box = 0

We need to find about how many shells does Sara have.

To find that we will just multiply (number of boxes) by (number of seashell in 1 box). Which is given by 7 times 0.

we know that product of a number and 0 is always 0.

Hence final answer is 0 seashell.

3 0

3 years ago