2 years ago

How do you graph y=3x^2

1 answer:

8 0

So because it's x^2 that means it's a parabola. The 3 before it is it's stretch factor (slope, so instead of going over one up one it goes over one up 3)

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If a =5, 0, −1,find a vector b such that compab = 2.b = _______.

Arturiano [62]

Answer:

$b = (q,r , 5q-2\sqrt{26} )$

Step-by-step explanation:

From the question we are told that

The vector given is

$a = (5,0,-1)$

Also $comp_a b = 2$

Generally

$comp_a b = \frac{a \cdot b}{|a|}$

Here $|a|$ is the magnitude of a which is mathematically represented as

$|a| = \sqrt{5^2 + 0^2 +(-1)^2 }$

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b is vector which we will assume to have the following parameters

$b = (q , r , x)$

$comp_a b = \frac{(5,0,-1) \cdot (q,r,x)}{\sqrt{26} } = 2$

=> $\frac{5q + 0 -x}{\sqrt{26} } = 2$

=> $x = 5q-2\sqrt{26}$

Hence the vector be can be mathematically represented as

$b = (q,r , 5q-2\sqrt{26} )$

This means that the vector b is more than one value since it is made up of variable

This means that if

$q = 1\\r=1\\x =1$

Then

$b = (1,1,5-2\sqrt{26} )$

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Step-by-step explanation:

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