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Paha777 [63]
3 years ago
13

Help pls urgent :) plssss

Mathematics
1 answer:
Ket [755]3 years ago
7 0

Answer:

Fraction form: 1/8

Decimal form: 0.125

Step-by-step explanation:

Slope of line = [-6 - (-8)]/[8 - ( -8)]

= [-6 + 8]/[8 + 8]

= 2/16

= 1/8

= 0.125

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Sara is completing the square to find the maximum or minimum value of the function f(x) = (2 - x) (5 + x). What is the first ste
DanielleElmas [232]
Definitely multiply out the given factors:

f(x) = 10 + 2x - 5x - x^2, or  f(x) = -x^2 - 3x + 10
Find the derivative:  f '(x) = -2x - 3
Set the deriv. = to 0 and solve for x:  -2x = 3, and x = -3/2
This x = -3/2 is the x-coordinate of the max value.  The y-coord. is

f(-3/2) = (-3/2)^2 - 3(-3/2) + 10 = 21.25

I realize that this result does not agree with any of the four possible answers.  Please ensure that y ou have copied down this problem completely and correctly.

4 0
3 years ago
Is (2, 4) a solution of 2x – 7y &lt; -10?<br> Choose 1 answer:<br> A<br> Yes<br> B<br> No
iren2701 [21]

Answer: NO DEFINITLY NOT

Step-by-step explanation:

2,4 is on a COORDINATE PLANE not an equation plz mark me brainliest

5 0
3 years ago
Read 2 more answers
Cost A=0.6489<br><br> take the inverse cosine of both sides
Stolb23 [73]
I am not quite sure what the question asks for,
But this is what i assume it wants:

Cos A= 0.6489
In this given one, we basically find the size of the angle A
we do cosine inverse on both sides to get the size of the angle A
cos^{-1} : It looks like this in the calculator
cos^{-1} × cos A=cos^{-1}(0.6489)
(cos^{-1} and cos cancels out)
A=cos^{-1}(0.6489)
A=49.54°
check: 
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6 0
3 years ago
) f) 1 + cot²a = cosec²a​
notsponge [240]

Answer:

It is an identity, proved below.

Step-by-step explanation:

I assume you want to prove the identity. There are several ways to prove the identity but here I will prove using one of method.

First, we have to know what cot and cosec are. They both are the reciprocal of sin (cosec) and tan (cot).

\displaystyle \large{\cot x=\frac{1}{\tan x}}\\\displaystyle \large{\csc x=\frac{1}{\sin x}}

csc is mostly written which is cosec, first we have to write in 1/tan and 1/sin form.

\displaystyle \large{1+(\frac{1}{\tan x})^2=(\frac{1}{\sin x})^2}\\\displaystyle \large{1+\frac{1}{\tan^2x}=\frac{1}{\sin^2x}}

Another identity is:

\displaystyle \large{\tan x=\frac{\sin x}{\cos x}}

Therefore:

\displaystyle \large{1+\frac{1}{(\frac{\sin x}{\cos x})^2}=\frac{1}{\sin^2x}}\\\displaystyle \large{1+\frac{1}{\frac{\sin^2x}{\cos^2x}}=\frac{1}{\sin^2x}}\\\displaystyle \large{1+\frac{\cos^2x}{\sin^2x}=\frac{1}{\sin^2x}}

Now this is easier to prove because of same denominator, next step is to multiply 1 by sin^2x with denominator and numerator.

\displaystyle \large{\frac{\sin^2x}{\sin^2x}+\frac{\cos^2x}{\sin^2x}=\frac{1}{\sin^2x}}\\\displaystyle \large{\frac{\sin^2x+\cos^2x}{\sin^2x}=\frac{1}{\sin^2x}

Another identity:

\displaystyle \large{\sin^2x+\cos^2x=1}

Therefore:

\displaystyle \large{\frac{\sin^2x+\cos^2x}{\sin^2x}=\frac{1}{\sin^2x}\longrightarrow \boxed{ \frac{1}{\sin^2x}={\frac{1}{\sin^2x}}}

Hence proved, this is proof by using identity helping to find the specific identity.

6 0
3 years ago
Which point is a solution to y&gt;2X-1
ivann1987 [24]

Answer:

Step-by-step explanation:

3 0
4 years ago
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