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-Dominant- [34]
3 years ago
14

99,000 equals how much tens

Mathematics
2 answers:
jok3333 [9.3K]3 years ago
5 0
The answer is 9,900 tens.
In-s [12.5K]3 years ago
3 0
9900  because you divide 99000 by 10
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Sara and 3 of her friends went to lunch one day. Each person paid for her own lunch, but they agreed to split the tip. If the ti
Slav-nsk [51]

Answer: well the answer is 9

Step-by-step explanation:

8 0
2 years ago
Help please algebra 2
lbvjy [14]
Answer: c

Explanation: this is because the end behavior approaches negative infinity on the left side and positive infinity on the right side.
8 0
3 years ago
Just for verification can anyone tell me what (-23) x (-4) is?
jarptica [38.1K]

Answer:

92

Step-by-step explanation:

Multiplying two negatives together results in a positive.

-23 * -4 = 23 * 4 = 92

7 0
3 years ago
Read 2 more answers
For the geometric sequence 1,2,4 find a8
Dennis_Churaev [7]
First, create a rule for this sequence.

Let a(1) be the first term (which here happens to be 1).

The next term, a(2), is twice the previous term, that is, twice 1, or 2.

a(3) = 2a(2) = 2(2) = 4

This is called a "recursive function."

The 3rd term is 4.  The next, which is a(3) is 2*4, or 8.


Note that there's an alternative approach.  The first term, a(1), is 1; the next is a(2) = a(1)*2^(2-1)   =  1*2^1=2
the next is a(3) = 1*2^(3-1) = 1*2^2 = 4

So the rule is   a(n) = a(1)*2^(n-1).

So a(8) is a(1)*2^(8-1)   =    1*2^7  = 2^3*2^4  =   8(16) = 128


4 0
3 years ago
In circle A shown, BC || DE , mBC=58° and mDE=142°. Determine the measure of ZCFE . Show how you arrived at your answer. CORRECT
scoray [572]

We have been given an image of a circle A, where BC || DE , mBC=58° and mDE=142°. We are asked to find the measure of angle CFE.  

Since segment DC is parallel to segment DE, so measure of arc BD will be equal to arc CE.

\widehat{BD}=\widehat{CE}

We know that sum of all arcs of a circle is equal to 360 degrees. So we can set an equation as:

\widehat{BD}+\widehat{CE}+\widehat{BC}+\widehat{DE}=360^{\circ}

Since \widehat{BD}=\widehat{CE}, so we will get:

\widehat{CE}+\widehat{CE}+\widehat{BC}+\widehat{DE}=360^{\circ}

2\widehat{CE}+\widehat{BC}+\widehat{DE}=360^{\circ}

2\widehat{CE}+58^{\circ}+142^{\circ}=360^{\circ}

2\widehat{CE}+200^{\circ}=360^{\circ}

2\widehat{CE}+200^{\circ}-200^{\circ}=360^{\circ}-200^{\circ}

2\widehat{CE}=160^{\circ}

\frac{2\widehat{CE}}{2}=\frac{160^{\circ}}{2}

\widehat{CE}=80^{\circ}

Therefore, the measure of arc CE is 80 degrees.

We can see that angle CFE is inscribed angle of arc CE, so measure of angle CFE will be half the measure of arc CE.

\angle CFE=\frac{80^{\circ}}{2}

\angle CFE=40^{\circ}

Therefore, the measure of angle CFE is 40 degrees.

4 0
3 years ago
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