Answer:
The first five terms of the given sequence
3, 6, 11, 18, 27
Step-by-step explanation:
It is given that,
an=n² +2
<u>To find the first five terms</u>
a₁ = 1² + 2 = 1 + 2 = 3
a₂ = 2² + 2 = 4 + 2 = 6
a₃ = 3² + 2 = 9 + 2 = 11
a₄ = 4² + 2 = 16 + 8 = 18
a₅ = 5² + 2 = 25 + 2 = 27
Therefore the first five terms of the given sequence
3, 6, 11, 18, 27
Hello :
y = 3x²+9x
= 3(x² + 3x )
= 3 ( x² +2(3/2)x +(3/2)²) -(3/2)²)
= 3((x+3/2)² -9/4)
y = 3 (x+3/2)² -27/4
<span>the x-coordinate of the vertex is : - 3/2</span>
The square root parent function is:
B. F(x)= √x
Answer:
q .no d
Step-by-step explanation:
64p^3+125
4p^3+ 5^3
(4p+ 5 ) ( 4p^2- 4p *5 + 5^2)
(4p+5) (16p- 20p+ 25)
The equation is a circle centered at the origin with radius 8 (sqrt(64))
Therefore, the bounded region is just a quarter circle in the first quadrant.
Riemann Sum: ∑⁸ₓ₋₋₀(y²)Δx=∑⁸ₓ₋₋₀(64-x²)Δx
Definite Integral: ∫₀⁸(y²)dx=∫₀⁸(64-x²)dx
