Represent the following with an equation.

Two trees are in a garden. The 20-foot tree casts a shadow four feet long. If the other tree is 15-foot tall, how long will its

Usimov [2.4K]

20/4 = 15/x
20x = 60
x = 3 feet
choice (1.) is the answer

5 0

3 years ago

Which student factored the expression x3 - 7x - x2 + 7 correctly based on their answer below?

Verizon [17]

We can check the end terms first

for
(a+b)(c+d), the first term of the expanded is ac and the last term is bd

so
the expanded is x^3 and last is +7

jane will have a lst term of -7 so no
mariah wil have last term of -7 as well, so no
only rojer and nethan have last tem of +7

so we can do the rest of it by doing the OL part of FOIL

do either roger or nethan
let's do nethan

F=x^3
O=-7x
I=-x^2
L=7
yep

it is nethan

4 0

4 years ago

Darla found that the least common denominator needed to subtract \frac{x}{x^2+4x-12}-\frac{3}{x+6}is (x + 6)(x – 2). Which is th

Leona [35]

<h3>Answer: Choice B</h3>

$\frac{x}{(x+6)(x-2)} - \frac{3(x-2)}{(x+6)(x-2)}$

which is the same as x/((x+6)(x-2)) - 3(x-2)/((x+6)(x-2))

=====================================

Explanation:

The LCD is (x+6)(x-2) which is the factorization of x^2+4x-12, and that is the denominator of the first fraction. The first fraction has the LCD already. The second fraction does not. It has (x+6) but it is missing (x-2).

We multiply top and bottom of the second fraction by (x-2) to get the second fraction to have the LCD.

$\frac{3}{x+6}$ turns into $\frac{3}{x+6}*\frac{x-2}{x-2} = \frac{3(x-2)}{(x+6)(x-2)}$