<span>△ABC∼△DEF
</span>Height of <span>△ABC: h1=20 inches
</span>Height of △DEF: h2=24 inches
<span>Ratio of the area of △ABC to the area of △DEF: R=?
</span>
R=(h1/h2)^2
R=[ (20 inches) /(24 inches) ]^2
R=(5/6)^2
R=5^2/6^2
R=25/36
Answer: T<span>he ratio of the area of △ABC to the area of △DEF is 25/36</span>
Answer:
below
Step-by-step explanation:
4(3 + 1)(3 + 3)(3 + 5)(3 - 5)
4(4)(6)(8)(-2)
16(-96)= -1536
Dilation because the sides will not be the same size as the original
If a football player runs 5/6 of a mile every 3/4th of a hour, that means every 1/4th a hour he runs 1.5/6th of a mile.
That means every 15 minutes the football player runs .2 of a mile. That means that every hour he runs :
0.8 of a mile!
Answer:

Step-by-step explanation:
