Question

In your last 23 basketball games, you attempted 101 free throws and made 66. Find the experimental probability that you make a free throw. Write the probability as a percent, to the nearest tenth of a percent.
A. 65.3%
B. 69.8%
C. 69.7%
D. 65.7%

Answer 1

Answer:

A. 65.3%

Step-by-step explanation:

We have to find the probability of making a free throw.

The probability of an event can be found as

P(E)=n(E)/n(S)

Where n(E) demonstrates the number of occurring of event E and n(S) depicts the total number of outcomes in sample.

Let F be the event of making a free throw then

P(F)=n(F)/n(S)

where n(F)= 66 throws that are made in basketball games

n(S)=101 free throws that are attempted in basketball games

P(F)=66/101=0.653465

Considering the rounding to 3 decimal places

P(F)=0.653

which can be represented as 65.3%.

Thus, the probability of making a free throw is 65.3%.