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3 years ago

Compound Interest HelpHelp me to answer this question. 10 points!

Mathematics

1 answer:

ANEK [815]3 years ago

8 0

P=principal=$6000
t=time period=6 years

Option A
n=4 (compounded 4 times a year, or quarterly)
r=0.075
Future Amount
=P(1+r/n)^(nt)
=6000(1+0.075/4)^(4*6)
=$9370.746

Option B:
e=2.7182818284 (Napier's constant)
r=interest rate = 0.072
Final amount
= Pe^(rt)
=6000*e^(0.072*6)
=9242.011

Therefore option A is more profitable.

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Graph y=8.5xy=8.5xy, equals, 8, point, 5, x.

Morgarella [4.7K]

Answer:

A, B, E

Step-by-step explanation:

<u>Given equation</u>

y = 8.5x

<u>Answer choices</u>

A. The equation represents a proportional relationship.

TRUE, it is in the form of y = kx

B. The unit rate of change of y with respect to x is 8.5

TRUE, y = mx + b, the slope m = 8.5 is the rate of change

C. The slope of the line is 2/17

False, the slope is 8.5

D. A change of 17 units in x results in a change of 2 units in y.

False, a change of x = 17 results in 17*8.5 = 144.5 units in y

E. A change of 4 units in x results in a change of 34 units in y.

TRUE, because 4*8.5 = 34

3 0

2 years ago

I’m so confused. what is part B?

Alenkinab [10]

Answer:sorry

Step-by-step explanation:

8 0

3 years ago

Given the Arithmetic series A1+A2+A3+A4 7 + 11 + 15 + 19 + . . . + 91 What is the value of sum?

aivan3 [116]

Answer:

The value of the sum is 1078

Step-by-step explanation:

* Lets revise how to find the sum of the arithmetic series

- In the arithmetic series there is a constant difference between each

two consecutive terms

- Ex:

# 4 , 9 , 14 , 19 , 24 , .......... (+ 5)

# 25 , 15 , 5 , -5 , -15 , .......... (-10)

- So if the first term is a and the constant difference between each two

consecutive terms is d, then

U1 = a , U2 = a + d , U3 = a + 2d , U4 = a + 3d , ..........

- Then the nth term is Un = a + (n - 1)d

- The sum of n terms is Sn = n/2[a + L] , where L is the last term in

the series

* Lets solve the problem

∵ The arithmetic series is 7 + 11 + 15 + 19 + ......................... + 91

∴ The first term (a) is 7

∴ The last term is (L) 91

- Lets find the constant difference

∵ 11 - 7 = 4 and 15 - 11 = 4

∴ The constant difference (d) is 4

- Lets find the sum of the series from 7 to 91

∵ Sn = n/2[a + L]

∵ a = 7 and L = 91

∴ Sn = n/2[7 + 91]

- We need to know how many terms in the series

∵ L is the last term and equals 91 lets find its position in the series

∵ Un = a + (n - 1)d

∵ a = 7 , d = 4 and Un = 91

∴ 91 = 7 + (n - 1)(4) ⇒ subtract 7 from both sides

∴ 84 = (n - 1)(4) ⇒ divide both sides by 4

∴ 21 = n - 1 ⇒ add 1 to both sides

∴ n = 22

∴ The number of the terms in the series is 22

- Lets find the sum of the 22 terms (S22)

∴ S22 = 22/2[7 + 91]

∴S22 = 11[98] = 1078

* The value of the sum is 1078

4 0

3 years ago

Which number comes next in the series? 1 – 8 – 27 – 64 – 125 – 216 –?

dalvyx [7]

${7}^{3} = 343$

3 0

3 years ago

A basketball player is fouled while attempting to make a basket and receives two free throws. The opposing coach believes there

zzz [600]

Answer:

$P(X = 0) = 0.64$

$P(X = 1) = 0.11$

$P(X = 2) = 0.25$

b) 0.75 = 75% probability that he makes no more than one of the shots

Step-by-step explanation:

We have these following probabilities:

64% = 0.64 probability that he misses both shots, that is, makes none of them.

11% = 0.11 probability that he makes one shot.

25% = 0.25 probability that he makes both shots.

a. Construct the appropriate probability distribution. (Round your answers to 2 decimal places.)

Binomial probability distribution, in which P(X = x) is the probability of making x shots. So

$P(X = 0) = 0.64$

$P(X = 1) = 0.11$

$P(X = 2) = 0.25$

b. What is the probability that he makes no more than one of the shots? (Round your answer to 2 decimal places.)

$P(X \leq 1) = P(X = 0) + P(X = 1) = 0.64 + 0.11 = 0.75$

0.75 = 75% probability that he makes no more than one of the shots

7 0

3 years ago