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tankabanditka [31]
3 years ago
13

I need help with 13 please it’s due tomorrow

Mathematics
1 answer:
Yuliya22 [10]3 years ago
7 0

the step by step instructions r in the pics

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Drag the dots to plot (5.5, 4), (-7,1), and (0,–9).<br> y
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5.5 always goes between 5 and 6

remember (x,y) one of the dots goes on the exactly on the axis, you have to drag it down to -9 from the y-axis

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What kind of wave is shown
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longitudinal

Step-by-step explanation:

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179÷10 to the first power
Elena-2011 [213]
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36 + m = 54<br> 54 - 36 = m<br> 36 + 54 = m<br> 54 / 36 = m<br> 36 x 54 = m
luda_lava [24]

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4 years ago
Find the average rate of change of each function over the interval [0, 2]. Match each representation with its respective average
marishachu [46]
Average rate of change over interval [a,b]: r=[f(b)-f(a)]/(b-a)
In this case the interval is [0,2], then a=0, b=2
r=[f(2)-f(0)]/(2-0)
r=[f(2)-f(0)]/2

1) First function: h(x)
r=[h(2)-h(0)]/2
x=2→h(2)=(2)^2+2(2)-6
h(2)=4+4-6
h(2)=2
x=0→h(0)=(0)^2+2(0)-6
h(0)=0+0-6
h(0)=-6
r=[h(2)-h(0)]/2
r=[2-(-6)]/2
r=(2+6)/2
r=(8)/2
r=4

2) Second function: f(x)
A function, f, has an
x-intercept at (2,0)→x=2, f(2)=0
and a y-intercept at (0,-10)→x=0, f(0)=-10
r=[f(2)-f(0)]/2
r=[0-(-10)]/2
r=(0+10)/2
r=(10)/2
r=5

3) Third function: g(x)
r=[g(2)-g(0)]/2
From the graph:
g(2)=6
g(0)=2
r=(6-2)/2
r=(4)/2
r=2

4) Fourth function: j(x)
r=[j(2)-j(0)]/2
From the table:
x=2→j(2)=-8
x=0→j(0)=4
r=(-8-4)/2
r=(-12)/2
r=-6

Answer:
Pairs
1) h(x)     4
2) f(x)      5
3) g(x)     2
4) j(x)     -6
8 0
4 years ago
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