Question

A sequence is defined recursively using the equation f(n + 1) = f(n) – 8. If f(1) = 100, what is f(6)?

Answer 1

In this item, we assume that f(6) is the f(n + 1). Thus, n + 1 = 6. If we solve for the succeeding terms for this series given the first term which is 100, we get,

                 f(2) = 100 – 8 = 92

                f(3) = 92 – 8 = 84

               f(4) = 84 – 8 = 76

                f(4) = 76 – 8 = 68

                f(5) = 68 – 8 = 60

                 f(6) = 60 -8 = 52

Thus, the answer is 52.