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Alexeev081 [22]
3 years ago
11

Carrie can inspect a case of watches in two hours. Jerry inspects a case in five hours. After inspecting a case for a half an ho

ur, Carrie takes a break. In the mean time, Jerry takes over and completes the job, how long did this take him?
Mathematics
2 answers:
steposvetlana [31]3 years ago
4 0

Answer:

It will take Jerry 3 hr 45 minutes to complete the work.

Step-by-step explanation:

Let Jerry takes x hours.

Carrie's rate = 1/2 case/hr

Jerry rate's = 1/5 case/h

We know that work done =rate x time

So, Carrie work + Jerry work = 1 job complete

x = 15/4 =

= 3 hr 45 minutes

Hence, it will take Jerry 3 hr 45 minutes to complete the work.

masha68 [24]3 years ago
3 0
Write the hours as ratio

Carrie : Jerry
   2      :    5

Put this ratio in words, we say 'for every two hours Carrie takes to inspect a case, Jerry would need 5 hours'

Carrie has done 30 minutes on a case before taking a break. It means Carrie has 1.5 hours left on the case if she was to continue it. 

We need to work out the proportion of the time Jerry would take in comparison to 1.5 hours that Carrie would have taken.

First, we divide 2 by 1.5 ⇒ \frac{2}{1.5}= \frac{4}{3}

Then we divide 5 by 4/3 ⇒ \frac{5}{4/3} = \frac{5*3}{4} =3.75 hours

Jerry would have taken 3.75 hours to finish the rest of the case
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The sum of two numbers is 64. One number is 8 more than the other. What are the two numbers?
lisabon 2012 [21]

Answer:

28 and 36.

Step-by-step explanation:

Alright, so we are given that the sum of two numbers is 64. Based on this, we know that we are going to be adding because the question said "the sum of two numbers is 64." Sum is the answer to an addition problem. Lets write an equation.

We need a variable, let x be the variable which is the value of the smaller number.

the equation is x+x+8=64

x= to the smaller number

x+8= to the number that is eight more than x or the smaller number.

Before we isolate for x, we need to simplify the expression by combining the like terms.

x plus x equals 2x.

Therefore, we have 2x+8=64.

Our goal is to isolate x, so we need to subtract 8 from both sides. 8 mius 8 is 0, and 64 mius 8 is 56.

Now, we have 2x=56.

We still need to isolate x by dividing both sides by 2. 2 divided by 2 is 1, so we are left with 1x or x. 56 divided by 2 is 28.

x=28.

Great, we found what x or the smaller value is.

Now, we need to find the larger number.

Substitute x as 28 into x+8 to find the number that is 8 more than the smaller number or x. You'll then get 36. If you add 36 and 28, you get 64. Also, 36 is 8 more than 28, so this answer is correct.

Hope this helps!

4 0
3 years ago
PLEASE HELP..........................................
Scrat [10]
24 units
9+9+3+3 =24.
3 0
3 years ago
R= 10,15,20 S=20,25 R u S =
dolphi86 [110]
The answer to the question

6 0
3 years ago
What is 8(2x+5)=16x+40?
polet [3.4K]

Answer:

x = infinite amount of solutions

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Equality Properties

Step-by-step explanation:

<u>Step 1: Define Equation</u>

8(2x + 5) = 16x + 40

<u>Step 2: Solve for </u><em><u>x</u></em>

  1. Distribute 8:                                  16x + 40 = 16x + 40
  2. Subtract 40 on both sides:          16x = 16x
  3. Divide 16 on both sides:               x = x

Here we see that <em>x</em> does indeed equal <em>x</em>.

∴ <em>x</em> has an infinite amount of solutions.

3 0
2 years ago
F(x) = 4x² – 17x+3
Svet_ta [14]

Answer:

discriminant: 241

2 real roots

Step-by-step explanation:

The discriminant is the part of the quadratic equation that is under the sqare root

x=(-b±√(b²-4ac))/2a

discriminant: b²-4ac

We also know that a quadratic equation is in the form ax²+bx+c = 0, so we can plug in the values we know from our equation to find the discriminant.

a=4

b=-17

c=3

(-17)^2-4(4)(3)

We also know that if the discriminant

is positive we have 2 real roots

is 0 we have 1 real root aka a repeated real solution

is negative we have no real roots

8 0
3 years ago
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