5x = -1
x = -1/5 = -0.2
That means that any ordered pair for the line will be (-0.2, y)
You can put any number in for y.
So two ordered pairs could be:
(-0.2, 1)
and
(-0.2, 2)
Answer:
0.1 = 10% probability that the class length is between 51.5 and 51.7 min, that is, P(51.5 < X < 51.7) = 0.1.
Step-by-step explanation:
A distribution is called uniform if each outcome has the same probability of happening.
The uniform distributon has two bounds, a and b, and the probability of finding a value between c and d is given by:

The lengths of a professor's classes has a continuous uniform distribution between 50.0 min and 52.0 min.
This means that 
If one such class is randomly selected, find the probability that the class length is between 51.5 and 51.7 min.

0.1 = 10% probability that the class length is between 51.5 and 51.7 min, that is, P(51.5 < X < 51.7) = 0.1.
Answer:
The standard deviation will be: 2.1
Step-by-step explanation:
We know that standard deviation is basically the square root of variance.
Using the formula to calculate the standard deviation

As
so the standard deviation can be calculated as:
standard deviation 


Therefore, the standard deviation will be: 2.1
See below for the terms, coefficients, and constants in the variable expressions
<h3>How to determine the terms, coefficients, and constants in the variable expressions?</h3>
To determine the terms, coefficients, and constants, we use the following instance:
ax + by + c
Where the variables are x and y
- Then the terms are ax, by and c
- The coefficients are a and b
- The constant is c
Using the above as guide, we have:
A) 2b + 2ac+5
- Terms: 2b, 2ac, 5
- Coefficient: 2, 2 and 5
- Constant 5
B) 34abx + 16y +1
- Terms: 34abx, 16y, 1
- Coefficient: 34ab, 16
- Constant: 1
C) st +4u + v
- Terms: st, 4u, v
- Coefficient: 4
D) 14xy + 6
- Terms: 14xy, 6
- Coefficient: 14, 6
- Constant 6
E) 14x + 12y
- Terms: 14x, 12y
- Coefficient: 14, 12
F) 3+ 6-7+a
- Terms: 3, 6, -7, a
- Coefficient: 1
- Constant: 3, 6, -7
Read more about terms, coefficients, and constants at:
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