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3 years ago

What value of n makes this expression equals to 6 3n-(2+n)

Mathematics

1 answer:

coldgirl [10]3 years ago

6 0

N = 4
(3)(4)-(2+4) = 12 - 6 = 6

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Y/2*4-10/x+6 where x=5 and y=16

Sliva [168]

(16)/(2)*4-(10)/(5)+6= 36

6 0

3 years ago

Someone help me with this question please

Valentin [98]

Answer:

We will need 16 tiles

Step-by-step explanation:

Each tile has a width of 1/4 ft

We want to know how many will fill 4 ft

This is a division problem

4 ft wall/ 1/4ft tiles =

copy dot flip

4 * 4/1 = 16

We will need 16 tiles

5 0

3 years ago

Find the measures of the legs of isosceles triangle ABC if AB= 2x+4,BC= 3x-1,AC=x+1 and the perimeter of the triangle ABC is 34

Naddika [18.5K]

(2x+4) +(3x-1) +(x+1)=34
6x+4=34
x=5
AB=14, BC=14, AC=6

5 0

3 years ago

Read 2 more answers

Please Help! Please Help! Please Help!

cestrela7 [59]

1: Commutative Property
2: Distributive Property
3: Associative Property

I think that that is the right order. :D

5 0

3 years ago

If you are dealt 4 cards from a shuffled deck of 52 cards, find the probability of getting two queens and two kings.

Bingel [31]

Given:

If you are dealt 4 cards from a shuffled deck of 52 cards.

We need to determine the probability of getting two queens and two kings.

Probability of getting two queens and two kings:

The number of ways of getting two queens is $4C_2$

The number of ways of getting two kings is $4C_2$

Total number of cases is $52C_4$

The probability of getting two queens and two kings is given by

$\text {probability}=\frac{\text {No.of fanourable cases}}{\text {Total no.of cases}}$

Substituting the values, we get;

$probability=\frac{4C_2 \cdot 4C_2}{52C_4}$

Simplifying, we get;

$probability=\frac{6 (6)}{270725}$

$probability=\frac{36}{270725}$

$probability=0.000133$

Thus, the probability of getting two queens and two kings is 0.000133

7 0

3 years ago