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3 years ago

Which fraction converts to a repeating decimal? Question 8 options: A) 412 B) 48 C) 42 D) 410

1 answer:

3 0

Unfortunately, you have not shared any of the fractions in question. 412, 48, 42 and 410 are all "integer" or "whole" numbers. Please share the entire question.

Example: 48 2/3 can be re-written with a repeating decimal:

48 2/3 = 48.666666666 .....

You might be interested in

What is 30% of 70. show your work<br>

mamaluj [8]

Answer: 21

Step-by-step explanation:

we have two simple equations:

1) 70=100%

2) x=30%

where left sides of both of them have the same units, and both right sides have the same units, so we can do something like that:

70/x=100%/30%

6. Now we just have to solve the simple equation, and we will get the solution we are looking for.

7. Solution for what is 30% of 70

70/x=100/30

(70/x)*x=(100/30)*x - we multiply both sides of the equation by

70=3.33333333333*x - we divide both sides of the equation by (3.33333333333) to get x

70/3.33333333333=x

The fore, the answer is 21

8 0

3 years ago

Read 2 more answers

What doubles fact can I write to solve 4+5

GenaCL600 [577]

5+4❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤

5 0

3 years ago

Write down the 3rd term in the sequence given by: T(n) = n2 + n

Sergio [31]

The solution for the problem is:
I will first get the first five terms so that I could easily locate the third term of this problem:So, substituting the values:
T(1) = 1^2 = 1T(2) = 2^2 = 4T(3) = 3^2 = 9T(4) = 4^2 = 16T(5) = 5^2 =25
So the third terms is T(3) = 3^2 = 9

8 0

3 years ago

Question 2 of 5

AlekseyPX

Given:

The different recursive formulae.

To find:

The explicit formulae for the given recursive formulae.

Solution:

The recursive formula of an arithmetic sequence is $f(n)=f(n-1)+d, f(1)=a,n\geq 2$ and the explicit formula is $f(n)=a+(n-1)d$ , where a is the first term and d is the common difference.

The recursive formula of a geometric sequence is $f(n)=rf(n-1), f(1)=a,n\geq 2$ and the explicit formula is $f(n)=ar^{n-1}$ , where a is the first term and r is the common ratio.

The first recursive formula is:

$f(1)=5$

$f(n)=f(n-1)+5$ for $n\geq 2$ .

It is the recursive formula of an arithmetic sequence with first term 5 and common difference 5. So, the explicit formula for this recursive formula is:

$f(n)=5+(n-1)(5)$

$f(n)=5+5(n-1)$

Therefore, the correct option is A, i.e., $f(n)=5+5(n-1)$ .

The second recursive formula is:

$f(1)=5$

$f(n)=3f(n-1)$ for $n\geq 2$ .

It is the recursive formula of a geometric sequence with first term 5 and common ratio 3. So, the explicit formula for this recursive formula is:

$f(n)=5(3)^{n-1}$

Therefore, the correct option is F, i.e., $f(n)=5(3)^{n-1}$ .

The third recursive formula is:

$f(1)=5$

$f(n)=f(n-1)+3$ for $n\geq 2$ .

It is the recursive formula of an arithmetic sequence with first term 5 and common difference 3. So, the explicit formula for this recursive formula is:

$f(n)=5+(n-1)(3)$

$f(n)=5+3(n-1)$

Therefore, the correct option is D, i.e., $f(n)=5+3(n-1)$ .

6 0

3 years ago

Read 2 more answers

Translate in to Algebraic equation. I had some money and I gave away $20 the first day, gained 3 times my original amount on the

prohojiy [21]

Let x represent the amount of money you originally had. The algebraic expression would be: x-20+3×=80.
If you want to solve the equation, it would be: 4x=100, and x=100÷4, which equals 25. So your original money was $25.

5 0

3 years ago