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frez [133]
4 years ago
14

Could someone please help me with this and also explain? I'm not sure what to do here:/ (Will give brainiest if possible,if corr

ect)

Mathematics
1 answer:
Tcecarenko [31]4 years ago
4 0
The obtuse angles are all the same, and in order to find the acute angles you have to subtract the obtuse angle from 180 degrees.

Acute angles will be equal to 180-130 = 50 degrees.
All the obtuse angles will be the same and all the acute angles will be the same. 
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Read 2 more answers
Help me with my math quiz from friday 4/1 <br> SHOW STEPS
malfutka [58]

Hie!! I will be solving the questions in the sequence of the attachments.

_______________________________________

4. As line SU and TV are intersecting each other at O.

A.T.Q, ∠UOV = (7x - 4)°

∠SOT = 87°

Then, ∠UOV = ∠SOT {Vertically Opposite Angles}

\rightarrow\sf{7x - 4=87}

\rightarrow\sf{7x =87+4}

\rightarrow\sf{7x =91}

\rightarrow\sf{x =\frac{91}{7}}

\rightarrow\boxed{\bf{x =13}}

_______________________________________

5. radius = 17ft

circumference of circle = 2πr

\rightarrow\sf{circumference=2\times\frac{22}{7}\times17}

\rightarrow\boxed{\bf{circumference=106.8ft}}

_______________________________________

3. ∠1 and ∠2 - add to 180 (linear pair)

∠1 and ∠3 - equal (Vertically Opposite Angles)

∠3 and ∠4 - add to 180 (linear pair)

∠2 and ∠4 - equal (Vertically Opposite Angles)

_______________________________________

2. 160° + (6x - 16)° = 180° (linear pair)

\rightarrow\sf{6x - 16 = 180-160}

\rightarrow\sf{6x - 16 = 20}

\rightarrow\sf{6x = 20+16}

\rightarrow\sf{6x =36}

\rightarrow\sf{x =\frac{36}{6}}

\rightarrow\boxed{\bf{x =6}}

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