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3 years ago

A line passes through the points (8, –1) and (–4, 2).

Mathematics

1 answer:

Yuki888 [10]3 years ago

8 0

Step-by-step explanation:

With the given points, we can first find the gradient of the line:

gradient = (2+1)/(-4-8)

= -1/4

We also know that the formula of a straight line is

Y = mX+C, where m is gradient and C is y intercept.

Hence by substituting the coordinates (-4, 2) and the gradient -1/4, we get:

2 = (-1/4)(-4) + C

<u>C = 1</u><u>.</u> Hence, Answer is C.

(Actually, you can just draw a straight line connecting the 2 coordinates and find out the y intercept)

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What is the value of cosθ given that (−2, −3) is a point on the terminal side of θ ?

snow_tiger [21]

Answer:

-0.555

Step-by-step explanation:

The terminal point of the vector in this problem is

(-2,-3)

So, it is in the 3rd quadrant.

We want to find the angle $\theta$ that gives the direction of this vector.

We can write the components of the vector along the x- and y- direction as:

$v_x = -2\\v_y = -3$

The tangent of the angle will be equal to the ratio between the y-component and the x-component, so:

$tan \theta = \frac{v_y}{v_x}=\frac{-3}{-2}=1.5\\\theta=tan^{-1}(1.5)=56.3^{\circ}$

However, since we are in the 3rd quadrant, the actual angle is:

$\theta=180^{\circ} + 56.3^{\circ} = 236.3^{\circ}$

So now we can find the cosine of the angle, which will be negative:

$cos \theta = cos(236.3^{\circ})=-0.555$

7 0

3 years ago

The Answer and yea idk

oksano4ka [1.4K]

(1-2)
(4-2)
the answer would be
-1/2 :)

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3 years ago

In order to estimate the height of a building, two students stand at a certain distance from the building at street level. from

enyata [817]

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.. h = (300 ft)/(1/tan(39°) -1/tan(50°))
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