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3 years ago

2x^2+15x+7 (box method)

Mathematics

1 answer:

RoseWind [281]3 years ago

4 0

(2x+1) (x+7)

I solved it by using the FOIL method, but you get the same answer either way

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Find the range of 5,3,1,1,3,3,4,4,4,1,1,4,2,2,5,5,5,2,5,5

ExtremeBDS [4]

Answer: 4

find the largest number (5) and take away the smallest (1)

5-1=4

6 0

2 years ago

Paul needs to buy 5_8pound of peanuts. The scale at the store measures parts of a pound in sixteenths. What measure is equivalen

ryzh [129]

Answer:

10 ÷ 16

Step-by-step explanation:

The computation is shown below

Given that

Paul required to buy 5 by 8 pound of peanuts

And, the scale at the store is in sixteenths

So, the measure that should be equivalent is

Here the denominator should be 16 so it should be multiplied by 2

= 5 ÷ 8 × 2 ÷ 2

= 10 ÷ 16

3 0

2 years ago

Solve 9x^2- 17x- 85 = 0 Give your solutions correct to 3 significant figures.

dybincka [34]

Answer:

$x =\frac{17}{18} +\frac{1}{18} \sqrt{3349}$ OR $x =\frac{17}{18} +\frac{-1}{18} \sqrt{3349}$

Step-by-step explanation:

9x2−17x−85=0

For this equation: a=9, b=-17, c=-85

9x2+−17x+−85=0

Step 1: Use quadratic formula with a=9, b=-17, c=-85.

$x =\frac{-b + \sqrt{b^{2}-4ac } }{2a}$

$x =\frac{-(-17)+\sqrt{(-17)^{2} -4(9)(-85)} }{2(9)}$

$x =\frac{17}{18} +\frac{-1}{18} \sqrt{3349}$

4 0

2 years ago

Show work

nika2105 [10]

Let's call the distance from the beach to the playground x.
Let's call the distance from the stand to the parking lot z.
Let's call the base of the biggest triangle in the picture (from the parking lot to the left) y.

Recall the pythagorean theorem: the sum of the squares of the legs of a right triangle is equal to the square of the hypotenuse.

There are three right triangles we can work with.

Triangle with sides 48, x and z. Here z is the hypotenuse so we get the equation $x^{2} + 48^{2} = z^{2}$

Triangle with sides 27, x and y. Here y is the hypotenuse so we get $27^{2} + x^{2} = y^{2}$

Triangle with sides z, y and (48+27). Here (48+27) is the hypotenuse so we get $y^{2} + z^{2} = (27+48)^{2}$ . That is, $y^{2} + z^{2} = 5625$

We have 3 equations and 3 unknowns (x, y and z). So let's take the last equation: $y^{2} + z^{2} = 5625$ and replace $z^{2}$ and $y^{2}$ using expressions that contain an expression in terms of x from the first two equations we came up with.

That gives us: $48^{2} + x^{2} + x^{2} + 27^{2} =5625$ which we solve for x as follows:

$2 x^{2} + 3033 =5625
2x^{2} =2592
 x^{2} =1296
x=36$

Now that we know x we can substitute 36 for x into the equation $48^{2} + x^{2} = z^{2}$ and solve for z as follows:
$48^{2} + 36^{2} = z^{2} 
2304+1296=z^{2} 
3600=z^{2} 
z=60$

This means that the distance from the beach to the parking lot is 36 m and the distance from the stand to the parking lot is 60 m.

4 0

3 years ago

Read 2 more answers

Simplify before multiplying 5/6×9/10

dangina [55]

9/12 is the answer, you can't simply then down anymore

3 0

3 years ago