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djverab [1.8K]
3 years ago
14

Find the root that is a real number. rootindex 4 startroot 4096 endroot

Mathematics
2 answers:
MAXImum [283]3 years ago
8 0

Answer: 8

Step-by-step explanation:\sqrt[4]{4096}

We need to factor this, so

4096|2\\2048|2\\1024|2\\512|2\\256|2\\128|2\\64|2\\32|2\\16|2\\8|2\\4|2\\2|2\\1

4096 = 2^{12}

We have to remember that x^{n+m}=x^{n}.x^{m}

This way, we have \sqrt[4]{4096}=\sqrt[4]{2^{12}} = \sqrt[4]{2^{4}.2^{4}.2^{4}}  = 2.2.2=8

Sati [7]3 years ago
6 0
The answer would be C.

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